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mars1129 [50]
4 years ago
7

Mercuric oxide (HgO) is heated and forms liquid mercury (Hg) and oxygen (O2) gas. How would you characterize this reaction?

Chemistry
1 answer:
My name is Ann [436]4 years ago
7 0

Answer:

Decomposition reaction.

Explanation:

Decomposition reaction -

It is the type of reaction, where a single entity breaks down into various products under the influence of some external factors , like heat and sunlight , is referred to as a decomposition reaction.

From the question,

The reaction is -

2 HgO  →  2 Hg + O₂

Hence ,

A single compound HgO breaks down to two entities , i.e. , Hg and  O₂.

             

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Answer:

A.) DNA is a double helix, and RNA is a single strand.



C.) DNA is involved only in transcription, and RNA is involved in both transcription and translation.



E.) DNA does not have uracil as a nitrogen base, but RNA does have uracil as a nitrogen base.











Explanation:

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#TheWizzer

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Answer: Compound

Explanation:

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Use the Henderson-Haaselbach equation based on the buffer equilibrium reaction to complete the statements below.
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3 years ago
Are silver spoons tarnished and turned black, chemical or physical property?
zavuch27 [327]
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4 0
4 years ago
A chemistry student weighs out 0.09666 g of phosphoric acid (H3PO4), a triprotic acid, into a 250.volumetric flask and dilutes t
Ber [7]

Answer: 14.62 ml

Explanation:

Molarity is defined as the number of moles of solute dissolved per liter of the solution.

Molarity=\frac{n\times 1000}{V_s}

where,

n= moles of solute  

V_s = volume of solution in ml = 250 ml

{\text {moles of solute}=\frac{\text {given mass}}{\text {molar mass}}=\frac{0.09666g}{98g/mol}=9.9\times 10^{-4}

Now put all the given values in the formula of molarity, we get

Molarity=\frac{9.9\times 10^{-4}\times 1000}{250ml}

Molarity=3.9\times 10^{-3}M

To calculate the volume of base, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is H_3PO_4

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is NaOH.

We are given:

n_1=3\\M_1=3.9\times 10^{-3}M\\V_1=250mL\\n_2=1\\M_2=0.2000M\\V_2=?

Putting values in above equation, we get:

3\times 3.9\times 10^{-3}\times 250=1\times 0.2000\times V_2\\\\V_2=14.62ml

Thus the volume of NaOH solution the student will need to add to reach the final equivalence point is 14.62 ml

8 0
3 years ago
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