All categories

3 years ago

PLEASE SOMEONE HELP ME I WILL GIVE YOU EVERY POINT POSSIBLE

Mathematics

1 answer:

Sidana [21]3 years ago

8 0

Answer:

$log_{b}( {m}^{p} ) = p \: log_{b}(m)$

You might be interested in

The sum of the present ages of the mother and her daughter is 80 years. The mother was thrice as old as her daughter when she wa

Alika [10]

Answer:

let the daughter age be x

let mother age be 3x

Step-by-step explanation:

x+3x= 80

4x = 80

x= 80\4

x=20

daughter age is 20

mather age= 80 -20

= 60

daughter age 20

mother age 60

7 0

3 years ago

What is the lcd for the fractions 5/12 and 7/18?

Yakvenalex [24]

Denoms are 12 and 18

12=2*2*3
18=2*3*3
lcd=2*2*3*3=36

lcd=36

3 0

3 years ago

A)12/35<br> B)37/35<br> C)12/37<br> D)35/12 <br> Please help

Licemer1 [7]

It's 12/35 because tangent is opposite over adjacent, so 12 is opposite of angle M and 35 is adjacent of angle M

If you want to remember cosine, sine, and tangent just remember
SOH CAH TOA

8 0

3 years ago

Help please

mrs_skeptik [129]

It will be 1.104 so i think it will be that ikd

6 0

4 years ago

PLEEEEEEEAAAAAAASSSSSSSSSSEEEEEEEEEEE help me!!!!!!!!!!

defon

Answer:

$\boxed{\sf \ \ \ \dfrac{18}{(x-7)(x+12)(x+30)} \ \ \ }$

Step-by-step explanation:

hello,

first of all we will study the quadratic expressions

we can write that, (the different answers provide good clues :-) )

$x^2+5x-84=(x-7)(x+12)$

and

$x^2+23x-210=(x-7)(x+30)$

so first of all as we cannot divide by 0 we need to take x different from 7, -12 and -30 and then we can write

$\dfrac{1}{x^2+5x-48}-\dfrac{1}{x^2+23x-210}=\dfrac{1}{(x-7)(x+12)}-\dfrac{1}{(x-7)(x+30)}\\\\=\dfrac{(x+30) -(x+12)}{(x-7)(x+12)(x+30)}=\dfrac{x+30-x-12}{(x-7)(x+12)(x+30)}\\\\=\dfrac{18}{(x-7)(x+12)(x+30)}$

hope this helps

7 0

3 years ago