Question

When Mrs. Myles gave a test, the scores were normally distributed with a mean of 72 and a standard deviation of 8. This means that 95% of her students scored between which two scores?

Answer 1

  Given a standardized test with a mean score of 78 and a standard deviation of 5.9, a student who scored in the 60th percentile could have a score of:
a.  84
b.  72
c.  79
d.  76
 the answer is c

Answer 2

Answer:

The score of Mr.Myles is between 56 and 88.  

Step-by-step explanation:

Given : When Mrs. Myles gave a test, the scores were normally distributed with a mean of 72 and a standard deviation of 8.

To find : The class interval at 95% of her students scored between which two scores?

Solution :

We have given,

Mean $\mu=72$

Standard deviation $\sigma=8$                  

The class interval at 95% is given by

$\mu-2\sigma\leq CI\leq \mu+2\sigma$                

Substitute the values in the formula,

$72-2(8)\leq CI\leq 72+2(8)$      

$72-16\leq CI\leq 72+16$              

$56\leq CI\leq 88$    

Therefore, The score of Mr.Myles is between 56 and 88.