1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
gayaneshka [121]
3 years ago
10

In a company, 70% of the workers are men. If 1,620 people work for the company who aren't men, how many workers are there in all

? ​
Mathematics
2 answers:
Zepler [3.9K]3 years ago
7 0
<h2>         (っ◔◡◔)っ ♥ Hey Honey Here! ♥</h2>

Answer:

2106<em>!</em>

Step-by-step explanation:

1,620 - 70% = 486

486 + 1,620 = 2106

(  お力になれて、嬉しいです<em>!</em>)

GenaCL600 [577]3 years ago
5 0

Answer:

5,400 total workers

Step-by-step explanation:

70% of workers are men, this means that 30% of workers aren't men

This means that 1,620 is 30% of the total workers

To figure out the total workers you do:

30 (percentage that represents the value)/100 = 1,620 (value) / x (total workers)

You then cross-multiply the equation by multiple the numbers diagonal each other:

30/100

=1,620/x

So, 30x = 162,000

You then isolate the variable

30x/30 = 162,000/30

x = 5,400

You might be interested in
Can some one pls help
Doss [256]

Answer:

I will try

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
ANSWER FAST PLZ 25 POINTS!!!!!!!!!!!!!!!
liberstina [14]

Answer:

44?

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Consider the function below. f(x)= x^3 + 2x^2 - x - 2 plot the x and y intercepts of the function
dimulka [17.4K]

In the Figure below is shown the graph of this function. We have the following function:

f(x)=x^3+2x^2-x-2

The y-intercept occurs when x=0, so:

f(0)=(0)^3+2(0)^2-(0)-2=-2

Therefore, the y-intercept is the given by the point:

\boxed{(0,-2)}

From the figure we have three x-intercepts:

\boxed{P_{1}(-2,0)} \\ \boxed{P_{2}(-1,0)} \\ \boxed{P_{3}(1,0)}

So, the x-intercepts occur when y=0. Thus, proving this:

f(x)=x^3+2x^2-x-2 \\ \\ For \ P_{1}:\\ If \ x=-2, \ y=(-2)^3+2(-2)^2-(-2)-2=0 \\ \\ For \ P_{2}:\\ If \ x=-1, \ y=(-1)^3+2(-1)^2-(-1)-2=0 \\ \\ For \ P_{3}:\\ If \ x=1, \ y=(1)^3+2(1)^2-(1)-2=0

7 0
3 years ago
Read 2 more answers
Which best describes the meaning of the statement if A then B
Oliga [24]

Answer:

a => b   \equiv   ( \neg a   \ \lor   \ b )

Step-by-step explanation:

You can understand the statement from many perspectives, but in terms of proposition logic it is best to understand it as   "negation of a" or "  b" in mathematical terms is written like this

a => b   \equiv   ( \neg a   \ \lor   \ b )

You can show that they are logically equivalent because they have the same truth table.

 

3 0
3 years ago
Find the remaining trigonometric ratios of θ if csc(θ) = -6 and cos(θ) is positive
VikaD [51]
Now, the cosecant of θ is -6, or namely -6/1.

however, the cosecant is really the hypotenuse/opposite, but the hypotenuse is never negative, since is just a distance unit from the center of the circle, so in the fraction -6/1, the negative must be the 1, or 6/-1 then.

we know the cosine is positive, and we know the opposite side is -1, or negative, the only happens in the IV quadrant, so θ is in the IV quadrant, now

\bf csc(\theta)=-6\implies csc(\theta)=\cfrac{\stackrel{hypotenuse}{6}}{\stackrel{opposite}{-1}}\impliedby \textit{let's find the \underline{adjacent side}}&#10;\\\\\\&#10;\textit{using the pythagorean theorem}\\\\&#10;c^2=a^2+b^2\implies \pm\sqrt{c^2-b^2}=a&#10;\qquad &#10;\begin{cases}&#10;c=hypotenuse\\&#10;a=adjacent\\&#10;b=opposite\\&#10;\end{cases}&#10;\\\\\\&#10;\pm\sqrt{6^2-(-1)^2}=a\implies \pm\sqrt{35}=a\implies \stackrel{IV~quadrant}{+\sqrt{35}=a}

recall that 

\bf sin(\theta)=\cfrac{opposite}{hypotenuse}&#10;\qquad\qquad &#10;cos(\theta)=\cfrac{adjacent}{hypotenuse}&#10;\\\\\\&#10;% tangent&#10;tan(\theta)=\cfrac{opposite}{adjacent}&#10;\qquad \qquad &#10;% cotangent&#10;cot(\theta)=\cfrac{adjacent}{opposite}&#10;\\\\\\&#10;% cosecant&#10;csc(\theta)=\cfrac{hypotenuse}{opposite}&#10;\qquad \qquad &#10;% secant&#10;sec(\theta)=\cfrac{hypotenuse}{adjacent}

therefore, let's just plug that on the remaining ones,

\bf sin(\theta)=\cfrac{-1}{6}&#10;\qquad\qquad &#10;cos(\theta)=\cfrac{\sqrt{35}}{6}&#10;\\\\\\&#10;% tangent&#10;tan(\theta)=\cfrac{-1}{\sqrt{35}}&#10;\qquad \qquad &#10;% cotangent&#10;cot(\theta)=\cfrac{\sqrt{35}}{1}&#10;\\\\\\&#10;sec(\theta)=\cfrac{6}{\sqrt{35}}

now, let's rationalize the denominator on tangent and secant,

\bf tan(\theta)=\cfrac{-1}{\sqrt{35}}\implies \cfrac{-1}{\sqrt{35}}\cdot \cfrac{\sqrt{35}}{\sqrt{35}}\implies \cfrac{-\sqrt{35}}{(\sqrt{35})^2}\implies -\cfrac{\sqrt{35}}{35}&#10;\\\\\\&#10;sec(\theta)=\cfrac{6}{\sqrt{35}}\implies \cfrac{6}{\sqrt{35}}\cdot \cfrac{\sqrt{35}}{\sqrt{35}}\implies \cfrac{6\sqrt{35}}{(\sqrt{35})^2}\implies \cfrac{6\sqrt{35}}{35}
3 0
3 years ago
Other questions:
  • A circle has a radius of square root 98 units and is centered at (5.9, 6.7). Write the equation of this circle. Please help!
    8·1 answer
  • A kinder garden class has 9 girls and 11 boys in class what percent of the class are girls
    10·2 answers
  • What is the equivalent ratios of 8:9
    10·2 answers
  • Find the average rate of change for f(x) = x2 − 8x + 15 from x = −3 to x = 2.
    5·1 answer
  • What is 4x+2y=16 in function form
    13·1 answer
  • Help me out pleaseee !! ​
    7·2 answers
  • Find the sum and express it in its simplest form. (6u-7c-6) + (-2u+4c)
    14·2 answers
  • Thomas rents a car for his vaccation the milliage included with the 54 miles forer every mile he drives over 54 miles he needs t
    6·1 answer
  • Which representation shows y as a function of x?
    7·2 answers
  • 1) Find the general solution to the following differential equation x^3•y’- y = 0
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!