Answer:
3.1415926535 8979323846 2643383279 50288419716939937510 5820974944 5923078164 06286208998628034825 3421170679 8214808651 32823066470938446095 5058223172 5359408128 48111745028410270193 8521105559 6446229489 54930381964428810975 6659334461 2847564823 37867831652712019091 4564856692 3460348610 4543266482.
Step-by-step explanation:
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Recall the Maclaurin expansion for cos(x), valid for all real x :

Then replacing x with √5 x (I'm assuming you mean √5 times x, and not √(5x)) gives

The first 3 terms of the series are

and the general n-th term is as shown in the series.
In case you did mean cos(√(5x)), we would instead end up with

which amounts to replacing the x with √x in the expansion of cos(√5 x) :

Answer:
Calculate the slope in the four intervals.
m = (f(b) - f(a)) / (b - a) slope in Intervall [a; b]
m1 = (3 - 0) / (2 - 0) = 1.5
m2 = (11 - 3) / (4 - 2) = 4
m3 = (23 - 3) / (6 - 2) = 5
m4 = (23 - 11) / (6 - 4) = 6
between x = 4 and x = 6 is the correct answer.