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liubo4ka [24]
2 years ago
9

What is the hypotenuse and how can you tell whether it's a hypotenuse or a short leg? Thx

Mathematics
2 answers:
Vaselesa [24]2 years ago
8 0
The hypotenuse is the longest side of a triangle and you can tell just by the measurements
neonofarm [45]2 years ago
3 0
The hypothenuse is the opposite side of the right angle

so that means that in this triangle the hypotenuse is 7
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Please answer this correctly
ipn [44]

Answer:

1

Step-by-step explanation:

Set the height of the bar to 1 because there is only 1 number between 40-49 i.e. 49

7 0
2 years ago
2<br> 3(9x - 6) = 4x + 10<br> What is the value of X In the equation
andreev551 [17]

Answer:

Step-by-step explanation:

23(9x-6) = 4x +10            

207x - 138 = 4x +10

203x = 148                                                    

x = 148/203

 or  

3(9x-6) = 4x +10

27x -18 = 4x + 10

   27x - 4x = 10 + 18

          23x = 28

x= 28/23

4 0
2 years ago
Jason used a graphing tool to find the equation of the line of best fit in this scatter plot. After reading the equation of the
anzhelika [568]

Answer: Jason likely MADE an error when working the equation in his notebook because ONLY THE Y-INTERCEPT MATCHES the slope and the y-intercept of the equation he wrote.

Step-by-step explanation:

8 0
3 years ago
Points M, N, and P are respectively the midpoints of sides AC , BC , and AB of △ABC. Prove that the area of △MNP is on fourth of
Hunter-Best [27]

Answer:

The area of △MNP is one fourth of the area of △ABC.

Step-by-step explanation:

It is given that the points M, N, and P are the midpoints of sides AC, BC and AB respectively. It means AC, BC and AB are median of the triangle ABC.

Median divides the area of a triangle in two equal parts.

Since the points M, N, and P are the midpoints of sides AC, BC and AB respectively, therefore MN, NP and MP are midsegments of the triangle.

Midsegments are the line segment which are connecting the midpoints of tro sides and parallel to third side. According to midpoint theorem the length of midsegment is half of length of third side.

Since MN, NP and MP are midsegments of the triangle, therefore the length of these sides are half of AB, AC and BC respectively. In triangle ABC and MNP corresponding side are proportional.

\triangle ABC \sim \triangle NMP

MP\parallel BC

MP=\frac{BC}{2}

By the property of similar triangles,

\frac{\text{Area of }\triangle MNP}{\text{Area of }\triangle ABC}=\frac{PM^2}{BC^2}

\frac{\text{Area of }\triangle MNP}{\text{Area of }\triangle ABC}=\frac{(\frac{BC}{2})^2}{BC^2}

\frac{\text{Area of }\triangle MNP}{\text{Area of }\triangle ABC}=\frac{1}{4}

Hence proved.

5 0
3 years ago
Find the distance between the points (7, 6) and (7, -4).
frutty [35]

Answer:

If I'm correct it is 10.

Step-by-step explanation:

The distance was 10 ;-;.

Tip: use desmos for this

4 0
3 years ago
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