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liubo4ka [24]
3 years ago
9

What is the hypotenuse and how can you tell whether it's a hypotenuse or a short leg? Thx

Mathematics
2 answers:
Vaselesa [24]3 years ago
8 0
The hypotenuse is the longest side of a triangle and you can tell just by the measurements
neonofarm [45]3 years ago
3 0
The hypothenuse is the opposite side of the right angle

so that means that in this triangle the hypotenuse is 7
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ABCD is a trapezoid. Point E is the midpoint of AD and point F is the midpoint of B.
VikaD [51]
2 cm. because you would subtract 5 and 3.
6 0
3 years ago
The perimeter of a rectangle is 150cm. The length is 15cm greater than the width. Find the dimensions
ANEK [815]
150/4 = 37.5cm. You divide by four because there are four sides on a rectangle. But 37.5 is the cm of a square. Since it says one of the sides is 15cm greater, you subtract 37.5 - 15 = 27.5cm on 2 of the width. While the other 2 lengths are greater than the width by 15 cm, so you add 15 to 37.5 which gives you 52.5cm. So the 2 width are 27.5cm and the length is 52.5cm.
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3 years ago
-3x-y=9
Lina20 [59]

Answer:

D: no solution

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4 0
3 years ago
X2 – 3x + 10<br><br> What is the answer to this?
Tpy6a [65]

Answer:

-1x+10

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Please help and thank you
tatiyna

Answer:

b_{1}=\frac{2A}{h}-b_{2}

Step-by-step explanation:

Given: A=\frac{1}{2}(b_{1} +b_{2})h

We need to completely isolate b_{1} to solve.

A=\frac{1}{2}(b_{1} +b_{2})h

A=(\frac{1}{2}b_{1} +\frac{1}{2} b_{2})h

A=\frac{1}{2}b_{1} h+\frac{1}{2}b_{2}h

-\frac{1}{2}b_{1}h+A=\frac{1}{2}b_{2}h

-\frac{1}{2}b_{1}h=-A+\frac{1}{2}b_{2}h

-\frac{1}{2}b_{1}=\frac{-A}{h}+\frac{1}{2}b_{2}

Finally, multiply both sides by -2 to completely isolate b_{1}.

b_{1}=\frac{2A}{h}-b_{2}

5 0
3 years ago
Read 2 more answers
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