I think it is the positive change about hiring the employs this way. watch this interview you will understand more percussively.
http://googletune.com/watch?v=M5LUFjQkqDA
Answer: Synchronization
Explanation:
In communication of messages between processes we have a mechanism called as the interprocess communication (IPC) using which it is required to achieve synchronization between the process. These synchronization helps to prevent collision of the processes for the shared resources. Examples can be of mechanism of producer consumer problem .
Answer: flash drive
Explanation:
Flash drives are refered to as small, portable storage devices which makes use of a USB interface in order to be connected to a laptop.
Flash cards are removable and rewritable. They are mainly used to store data. Flash cards can be found in computers, laptops, digital cameras etc.
When Libby wrote the email to her friend, she typed the '@' symbol. When pressing SHIFT and 2 together, it pastes this aforementioned symbol. However, there isn't any specific name for the symbol. As a matter as fact, there are several names that this symbol goes by.
The most famous name this symbol is called is the "at symbol" or the "at sign". In terms of a formal name, "commercial at" would be a good one.
Here's an example with the symbol:
[email protected]
This is essentially telling the email server where to send your email. From this, they'll know it's located at brainly.com! It's pretty neat.
Answer: provided in the explanation section
Explanation:
Given that:
Assume D(k) =║ true it is [1 : : : k] is valid sequence words or false otherwise
now the sub problem s[1 : : : k] is a valid sequence of words IFF s[1 : : : 1] is a valid sequence of words and s[ 1 + 1 : : : k] is valid word.
So, from here we have that D(k) is given by the following recorance relation:
D(k) = ║ false maximum (d[l]∧DICT(s[1 + 1 : : : k]) otherwise
Algorithm:
Valid sentence (s,k)
D [1 : : : k] ∦ array of boolean variable.
for a ← 1 to m
do ;
d(0) ← false
for b ← 0 to a - j
for b ← 0 to a - j
do;
if D[b] ∧ DICT s([b + 1 : : : a])
d (a) ← True
(b). Algorithm Output
if D[k] = = True
stack = temp stack ∦stack is used to print the strings in order
c = k
while C > 0
stack push (s [w(c)] : : : C] // w(p) is the position in s[1 : : : k] of the valid world at // position c
P = W (p) - 1
output stack
= 0 =
cheers i hope this helps !!!
