Given:
The vertex of a quadratic function is (4,-7).
To find:
The equation of the quadratic function.
Solution:
The vertex form of a quadratic function is:
...(i)
Where a is a constant and (h,k) is vertex.
The vertex is at point (4,-7).
Putting h=4 and k=-7 in (i), we get


The required equation of the quadratic function is
where, a is a constant.
Putting a=1, we get

![[\because (a-b)^2=a^2-2ab+b^2]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%28a-b%29%5E2%3Da%5E2-2ab%2Bb%5E2%5D)
Therefore, the required quadratic function is
.
113.25 because the middle ground of 1 - 150 students is 75 and then 1+150=151 2+149+151 but instead of doing that again and again just multiply the lowest number and the highest number by the middle ground
Answer:
K'(-3,-2) and A'(-2,5)
Step-by-step explanation:
180 degree rotation = (x,y)---(-x, -y)
hence, if k=(3,2)
then k' = (-3, -2)
90 degree rotation clockwise= (x,y)--(y,-x)
hence if, A=(-5 , -2)
then, A'= (-2, 5)
The 4th one, since both values have less than .5 after the decimal