Answer:
A: the proposed route is 3.09 miles, so exceeds the city's limit
Step-by-step explanation:
The length of the route in grid squares can be found using the Pythagorean theorem on the two parts of the route. Let 'a' represent the length of the route to the park from the start, and 'b' represent the route length from the park to the finish. Then we have (in grid squares) ...
a^2 = (12-6)^2 +3^2 = 45
a = √45 = 3√5
and
b^2 = (6 -2)^2 +4^2 = 32
b = √32 = 4√2
Then the total length, in grid squares, is ...
3√5 + 4√2 = 6.7082 +5.6569 = 12.3651
If each grid square is 1/4 mile, then 12.3651 grid squares is about ...
(12.3651 squares) · (1/4 mile/square) = 3.0913 miles
The proposed route is too long by 0.09 miles.
Answer:
y = -0.25x - 6
Step-by-step explanation:
You can either just read off the slope m = -0.25 and the intersection with the vertical n = -6 or you form a system of equations from points you choose on the graph. For example:
(0,-6);(4,-7)
The general equation for a line:
y = m*x + n
The two points on the graph form a system of two equations:
1. -6 = m*0 + n
2. -7 = m*4 + n
You can read off n right away fro equation 1:
n = -6
Plugging n into equation 2:
-7 = m*4 - 6 => -1 = m*4 => m = -1/4
Answer:
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Answer:
The length of the line segment UV is 76 units
Step-by-step explanation:
In a triangle, the line segment joining the mid-points of two sides is parallel to the third side and equal to half its length
In Δ ONT
∵ U is the mid-point of ON
∵ V is the mid-point of TN
→ That means UV is joining the mid-points of two sides
∴ UV // OT
∴ UV =
OT
∵ UV = 7x - 8
∵ OT = 12x + 8
∴ 7x - 8 =
(12x + 8)
→ Multiply the bracket by 
∵
(12x + 8) =
(12x) +
(8) = 6x + 4
∴ 7x - 8 = 6x + 4
→ Add 8 to both sides
∴ 7x - 8 + 8 = 6x + 4 + 8
∴ 7x = 6x + 12
→ Subtract 6x from both sides
∴ 7x - 6x = 6x - 6x + 12
∴ x = 12
→ Substitute the value of x in the expression of UV to find it
∵ UV = 7(12) - 8 = 84 - 8
∴ UV = 76
∴ The length of the line segment UV is 76 units
Answer:
see explanation
Step-by-step explanation:
∠2 and ∠3 are same- side interior angles and are supplementary.