Y=7 is just a straight horizonal line that is perpendicular to the y axis at 7
and y=1/2x+6, is in y=mx+b form where m=slope and b=yintercept so
to find the intersection, yo just find when both sentances are correct so
y=7
subsitute that into y=1/2x+6
7=1/2x+6
subtract 6 from both sides
1=1/2x
multiply both sides by 2
2=x
so the point (2,7) is the intersection
104 ÷ 5.1 = 20.3921
Nearest tenth 20.4
Answer:
Given: In parallelogram ABCD, AC=BD
To prove : Parallelogram ABCD is rectangle.
Proof : in △ACB and △BDA
AC=BD ∣ Given
AB=BA ∣ Common
BC=AD ∣ Opposite sides of the parallelogram ABCD
△ACB ≅△BDA∣SSS Rule
∴∠ABC=∠BAD...(1) CPCT
Again AD ∥ ∣ Opposite sides of parallelogram ABCD
AD ∥BC and the traversal AB intersects them.
∴∠BAD+∠ABC=180∘ ...(2) _ Sum of consecutive interior angles on the same side of the transversal is
180∘
From (1) and (2) ,
∠BAD=∠ABC=90∘
∴∠A=90∘ and ∠C=90∘
Parallelogram ABCD is a rectangle.
Answer:
x = 2 or
x = -7
Step-by-step explanation:
(x - 2)(x + 7) = 0
x - 2 = 0
Add 2 to both sides
x - 2 + 2 = 2 + 0
x = 2
OR
x + 7 = 0
Subtract 7 from both sides
x + 7 - 7 = 0-7
x = -7
Therefore
x = 2 or
x = -7
