Answer: 
Step-by-step explanation:
Since, The total number of student = 300
Out of which,
The number of students who are only in Maths = 120
And, The number of students who are only in Science = 50
While, the students who are not from any subject = 100
Hence, the number of student who are from both maths and science = Total student - Maths student (only) - science student (only) - None
= 300 - 120 - 50 - 100
= 30
That is, there are 30 students who are both from science and maths,
Thus, the probability of selecting one student who is both from maths and science = 30/300 = 1/10
Answer:
2a - b = 5
Step-by-step explanation:
4a - 2b = 10
take out the highest common factor of the left side
2(2a - b) = 10
divide both sides by two
2a - b = 10/2
2a - b = 5
Answer:
the hexagon is the right one
Answer:
P(-2) = 2(-2^4) - 5(-2^3) + (-2) -10
= 2(16) - 5(-8) + (-2) - 10
= 32+40-2-10
= 60
P(1) = 2(1^4) - 4(1^3) + (1) - 10
= 2 - 4 + 1 - 10
= -11
P(2). = 2(2^4) - 5(2^3) + (2) - 10
= 2(16) - 5(8) + 2 - 20
= 32-40+2-10
= -20