Given :
An alloy is a mixture of metals. Suppose that a certain alloy is made by mixing 50 g of an alloy containing 12% copper with 78 g of an alloy containing 92% copper.
To Find :
How many grams of copper are in the resulting mixture what percentage of the resulting mixture is copper.
Solution :
Mass of copper in 50 gm alloy = 
.
Mass of copper in 78 gm alloy = 
.
Total mass of copper, ( 6 + 76.44 ) gm = 82.44 gram.
Percentage of copper in resulting mixture :
Hence, this is the required solution.
Answer:
-2r-19p
Step-by-step explanation:
-4p-2r-15p
add like terms
-2r-19p
Answer:
-22/55,-1,21/28
Step-by-step explanation:
Answer
∴ The true statement is Answer:
The true statement is BD ≅ CE ⇒ 3rd answer
Step-by-step explanation:
- There is a line contained points B , C , D , E
- All points are equal distance from each other
- That means the distance of BC equal the distance of CD and equal
the distance of DE
∴ BC = CD = DE
- That means the line id divided into 3 equal parts, each part is one
third the line
∴ BC = 1/3 BE
∴ CD = 1/3 BE
∴ DE = 1/3 BE
∵ BC = CD
∴ C is the mid-point of BD
∴ BC = 1/2 BD
∵ CD = DE
∴ D is the mid-point of DE
∴ CD = 1/2 CE
- Lets check the answers
* BD = one half BC is not true because BC = one half BD
* BC = one half BE is not true because BC = one third BE
* BD ≅ CE is true because
BD = BC + CD
CE = CD + DE
BC ≅ DE and CD is common
then BD ≅ CE
* BC ≅ BD is not true because BC is one half BD
∴ The true statement is BD ≅ CE
plz mark me brainliest
Answer:
x=3, solution is not extraneous
Step-by-step explanation:
we have
Solve for x
squared both sides
<u><em>Verify</em></u>
For x=3
-----> is true
therefore
x=3, solution is not extraneous
