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andre [41]
3 years ago
9

Objects falling through air experience a type of friction called

Physics
1 answer:
Alik [6]3 years ago
7 0

Answer: Gravity

Explanation: If anything thing is falling its by gravity.

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A nonmechanical water meter could utilize the Hall effect by applying a magnetic field across a metal pipe and measuring the Hal
Serga [27]

Answer:

The velocity is  v =2.455 \  m/s

Explanation:

From the question we are told that  

   The diameter of the pipe is  d =  4.25 \ cm  = 0.0425 \ m

    The magnetic field is  B  =  0.575 \  T

     The hall voltage is  V_H =  60.0 mV  =  60 *10^{-3} \  V

Generally the average fluid velocity is mathematically represented as

          v = \frac{V}{ B  *  d }

=>       v = \frac{60*10^{-3}}{ 0.575   *  0.0425  }

=>       v =2.455 \  m/s

5 0
3 years ago
metal cap is the negative terminal of an electric cell true or false please send me the answer please​
USPshnik [31]

Answer:

false. it's positive terminal of an electric cell

7 0
3 years ago
If the forces are equal and opposite why does the rocket ship move
qaws [65]
<span>A rocket in its simplest form is a chamber enclosing a gas under pressure. A small opening at one end of the chamber allows the gas to escape, and in doing so provides a thrust that propels the rocket in the opposite direction. A good example of this is a balloon. Air inside a balloon is compressed by the balloon's rubber walls. The air pushes back so that the inward and outward pressing forces are balanced. When the nozzle is released, air escapes through it and the balloon is propelled in the opposite direction.</span>
7 0
3 years ago
A ball is hit 1 meter above the ground with an initial speed of 40 m/s. If the ball is hit at an angle of 30 above the horizonta
Vika [28.1K]

Answer:

t_t=4.131\ s

Explanation:

Given:

height above the horizontal form where the ball is hit, y=1\ m

angle of projectile above the horizontal, \theta=30^{\circ}

initial speed of the projectile, u=40\ m.s^{-1}

<u>Firstly we find the </u><u>vertical component of the initial velocity</u><u>:</u>

u_y=u.\sin\theta

u_y=40\times \sin30^{\circ}

u_y=20\ m.s^{-1}

During the course of ascend in height of the ball when it reaches the maximum height then its vertical component of the velocity becomes zero.

So final vertical velocity during the course of ascend:

  • v_y=0\ m.s^{-1}

Using eq. of motion:

v_y^2=u_y^2-2g.h (-ve sign means that the direction of velocity is opposite to the direction of acceleration)

0^2=20^2-2\times 9.8\times h

h=20.4082\ m (from the height where it is thrown)

<u>Now we find the time taken to ascend to this height:</u>

v_y=u_y-g.t

0=20-9.8t

t=2.041\ s

<u>Time taken to descent the total height:</u>

  • we've total height, h'=h+y =20.4082+1

h'=u_y'.t'+\frac{1}{2} g.t'^2

  • during the course of descend its initial vertical velocity is zero because it is at the top height, so u_y'=0\ m.s^{-1}

21.4082=0+4.9t'^2

t'=2.09\ s

<u>Now the total time taken by the ball to hit the ground:</u>

t_t=t'+t

t_t=2.09+2.041

t_t=4.131\ s

3 0
3 years ago
A toy car that is 0.12 m long is used to model the actions of an actual car that
kolezko [41]

Answer:

it is B 1:50

Explanation:

just did it on apex

3 0
4 years ago
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