Answer:
The rate of change of distance between the two ships is 18.63 km/h
Explanation:
Given;
distance between the two ships, d = 140 km
speed of ship A = 30 km/h
speed of ship B = 25 km/h
between noon (12 pm) to 4 pm = 4 hours
The displacement of ship A at 4pm = 140 km - (30 km/h x 4h) =
140 km - 120 km = 20 km
(the subtraction is because A is moving away from the initial position and the distance between the two ships is decreasing)
The displacement of ship B at 4pm = 25 km/h x 4h = 100 km
Using Pythagoras theorem, the resultant displacement of the two ships at 4pm is calculated as;
r² = a² + b²
r² = 20² + 100²
r = √10,400
r = 101.98 km
The rate of change of this distance is calculated as;
r² = a² + b²
r = 101.98 km, a = 20 km, b = 100 km
Warm air reminds me of osmosis
We have: Work done = Force × Displacement
Here, Force = 300 N
Displacement = 120 m
Substitute their values into the formula:
W = 300 × 120
W = 36000
In scientific notation, it would be: 3.6 × 10⁴
Finally, option C would be your correct answer.
Hope this helps!
Answer:......................................................................................
.Explanation:
Answer:
FAE= 0.014 N
Explanation:
The KE of block is decreased because of the slowing action of the friction force .
Change in KE of block = work done on block by friction ƒ
⠀ ➪ ½mu²ƒ - ½mu²i = Fƒs cos θ
Because the friction force on the block is opposite in direction to the displacement , cos θ = -1
➢ Using Uƒ = 0 , Vƒ = 0.20 m/s , and s = 0.70 m
✒ We find ,
➪½mu²ƒ - ½mu²i = Fƒs cos θ
➪0-½ (0.50 kg) (0.20 m/s)² = (Fƒ) (0.70 m) (-1)
➪ Fƒ = 0.014 N
Hope this helped, can i pls have brainliest
