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Ray Of Light [21]
3 years ago
15

A particular circle in the standard (x,y) coordinate

Mathematics
1 answer:
matrenka [14]3 years ago
7 0
For any circle with Cartesian equation
(x-a)^2 + (y-b)^2 = r^2,
we have that the centre of the circle is (a,b), and the radius of the circle is r.

So in the case that 
(x-5)^2 + y^2 = 38,
we essentially have that
a = 5, b = 0, r^2 = 38.

So the centre of the circle is (5,0), and the radius is \sqrt{38}.
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Find the 88th term of the arithmetic sequence 26, 28, 30, ...
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Answer:

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Step-by-step explanation:

The nth term of an arithmetic sequence is given as:

f(n) = a + (n - 1)d

where a = first term

d = common difference

The first term of the sequence is 26 and the common difference is 2 (28 - 26 = 2)

The 88th term of the sequence is therefore:

f(88) = 26 + (88 - 1)*2

f(88) = 26 + (87 * 2)

f(88) = 26 + 174

f(88) = 200

The 88th term is 200.

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