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lidiya [134]
3 years ago
14

What are the greatest common factors of 51 and 85

Mathematics
1 answer:
rusak2 [61]3 years ago
6 0
Greatest\ common\ factor\ is\ the\ highest\ number\ by\ which\ 51\ and\ 85\\
can\ be\ divided\\\\ 
51:51\\\\
85:5\\
17:17\\\\GCF=1\\\\Greatest\ common\ factor\ of\ 51\ and\ 85\ is\ equal\ to\ 1.

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I will mark either the best or the first answer brainliest.
posledela

Answer:

11.x=16 12.x=37

Step-by-step explanation:

11.

20^2-12^2=x^2

256=x^2

x=√256

x=16

12.

13^2-5^2=y^2

144=y^2

y=12

/

y^2+35^2=x^2

12^2+35^2=x^2

1369=x^2

x=37

5 0
3 years ago
Read 2 more answers
Prove the divisibility of the following numbers:
yan [13]
8^{10}-8^9-8^8=8^8(8^2-8-1)=8^8(55)

81^7-27^9-9^{13}=3^{28}-3^{27}-3^{26}=3^{26}(3^2-3-1)=3^{26}(5)=3^{24}(45)
8 0
3 years ago
In the largest clinical trial ever​ conducted, 401,974 children were randomly assigned to two groups. The treatment group consis
BARSIC [14]

Answer:

The requirements for the hypothesis test does satisfied the method for testing the claim that from two population proportions the rate of polio is less for children given the salk vaccine.

Step-by-step explanation:

The percentage of children in the treatment group was:

(201229/401974)*100 = 49.9%

The percentage of children given placebo was:

(200745/401974)*100 = 50.1%

The percentage of children that developed polio in the treatment group:

(33/200745)*100 = 0.0164%

The percentage of children that developed polio in the placebo group:

(115/201229)*100 = 0.0571%

The percentage difference between the two group:

((0.0571-0.0164)/0.0571) = 61.62%

Therefore:

The amount of children used for each group was almost divided into half of the total amount of children. The test revealed although very small percentages of the both group developed polio, 68.62% more children given placebo than the children that was given the salk vaccine. Therefore, the study shows that the rate of polio is less for children given the salk vaccine and the the hypthesis test is satisfied.

6 0
3 years ago
Can you help me to solve this​
Ber [7]

Answer:

\frac{4a-2}{2a+1}

Step-by-step explanation:

Factorise the numerator and denominator

8a² - 2 ← factor out 2 from each term

= 2(4a² - 1) ← 4a² - 1 is a difference of squares

= 2(2a - 1)(2a + 1)

4a² + 4a + 1 ← is a perfect square

= (2a + 1)²

Thus

\frac{8a^2-2}{4a^2+4a+1}

= \frac{2(2a-1)(2a+1)}{(2a+1)(2a+1)} ← cancel (2a + 1) on numerator/ denominator

= \frac{2(2a-1)}{2a+1}

= \frac{4a-2}{2a+1}

3 0
3 years ago
Read 2 more answers
Which expression is equal to 2x-17. A. -17+2x. B. -2x+17. C. -2x-17. D. 17+2x
Vilka [71]
-17+2x is equal to that
8 0
2 years ago
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