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8090 [49]
3 years ago
7

casey ran a 75 meter race in 10 seconds her distances at certain times during the race are shown in the table . what is the doma

in for the graph of the function that would model her race[  time in seconds 0 1 2 3 4 5 6 7 8 9 10 : distance in meters 0.0 5.5 12.0 20.0 28.5 36.0 44.0 56.5 64.0 75.0
Mathematics
1 answer:
Troyanec [42]3 years ago
7 0
The domain of the graph is everything x is allowed to equal. Parentheses are used to show that x can be everything up to, but not including that number. Brackets are used to show x can be anything up to, and including, that number. The comma between the two numbers indicates that x can be anything between those two numbers.

Here, the time goes on the x axis and the distance will go on the y axis.
Time: 0 1 2 3 4 5 6 7 8 9 10
<span>Distance: 0.0 5.5 12.0 20.0 28.5 36.0 44.0 56.5 64.0 75.0
</span>
Since we are dealing with the domain, we really only need to focus on the time.
Time: 0 1 2 3 4 5 6 7 8 9 10

From this, we see that the values go from 0 to 10. This means that x can be anything from 0 to 10. Because there are y values that correlate with the numbers 0 and 10, we know that the domain will include 0 and 10. This indicates we must use brackets. 

Knowing all of this information, we can now write our domain as:
[0, 10]
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3 years ago
A cup of coffee has approximately 310 mg of caffeine. Each hour, the caffeine in your system decreases by about 35%. How much ca
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Answer:

∴35.97 mg caffeine would be left in the system after 5 hours.

Step-by-step explanation:

Given that,

A cup of coffee has approximately 310 mg of caffeine.

Caffeine decrease at a rate 35% per hour.

Exponential Function:

y(t)=y_0(1-r)^t

y(t)= Amount caffeine after t hours

y_0= Initial amount of caffeine

r= rate of decrease

t = Time in hour.

Here y(t)=?, y_0 = 310 mg, r=35%=0.35, t= 5 hours

y(t)=310(1-0.35)^5

      =35.97 mg

∴35.97 mg caffeine would be left in the system after 5 hours.

3 0
4 years ago
Suppose that in a large metropolitan area, 84% of all households have cable tv. Suppose you are interested in selecting a group
Firdavs [7]

Answer:

0.05606

Step-by-step explanation:

This is a binomial probability distribution problem.

84% of all households have cable TV, thus;

p = 0.84

There are six households from this area, thus; n = 6

Formula for this binomial distribution is;

P(X) = C(n, x) × p^(x) × (1 - p)^(n - x)

We want to find the proportion of groups where at most three of the households have cable TV.

Thus, it's is;

P(X ≤ 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)

P(X = 0) = C(6, 0) × 0.84^(0) × (1 - 0.84)^(6 - 0) = 0.00001678

P(X = 1) = C(6, 1) × 0.84^(1) × (1 - 0.84)^(6 - 1) = 0.000528

P(X = 2) = C(6, 2) × 0.84^(2) × (1 - 0.84)^(6 - 2) = 0.006963

P(X = 3) = C(6, 3) × 0.84^(3) × (1 - 0.84)^(6 - 3) = 0.04855

Thus;

P(X ≤ 3) = 0.00001678 + 0.000528 + 0.006963 + 0.04855 = 0.05606

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The cost for a company to produce x smartphones can be modeled by C(x)= 2x+35 and the company's total profit after selling x sma
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D

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