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Nadya [2.5K]
3 years ago
9

If xvaries directly as y.x=5 and y=10. find theValue of a x when y=3​

Mathematics
1 answer:
Serggg [28]3 years ago
4 0

Answer:

x = 1.5 when y = 3

Step-by-step explanation:

You can put this in a ratio:

x    :    y

5    :   10

1.5  :    3

x is 1.5 when y is 3.

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Lena is converting 2/25 to a percent. What should she multiply the numerator and denominator of the fraction by to find the perc
NNADVOKAT [17]
A percent is a number out of 100, so you'd want to multiply the denominator to get 100. In this case, 25 would have to be multiplied by 4 to get 100. To keep the fractions equal to each other, you have to multiply the numerator by the same thing. 2*4=8. Therefore, your fraction would be 8/100 or 8%
7 0
3 years ago
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The number of customers waiting for gift-wrap service at a department store is an rv X with possible values 0, 1, 2, 3, 4 and co
julia-pushkina [17]

Answer:

P[X=3,Y=3] = 0.0416

Step-by-step explanation:

Solution:

- X is the RV denoting the no. of customers in line.

- Y is the sum of Customers C.

- Where no. of Customers C's to be summed is equal to the X value.

- Since both events are independent we have:

                         P[X=3,Y=3] = P[X=3]*P[Y=3/X=3]

              P[X=3].P[Y=3/X=3] = P[X=3]*P[C1+C2+C3=3/X=3]

        P[X=3]*P[C1+C2+C3=3/X=3] = P[X=3]*P[C1=1,C2=1,C3=1]        

              P[X=3]*P[C1=1,C2=1,C3=1]  = P[X=3]*(P[C=1]^3)

- Thus, we have:

                        P[X=3,Y=3] = P[X=3]*(P[C=1]^3) = 0.25*(0.55)^3

                        P[X=3,Y=3] = 0.0416

6 0
3 years ago
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Anton [14]
The answer to that question is C
8 0
3 years ago
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A lighthouse is built on an exposed reef, 4.5 miles off-shore. The shoreline is perfectly straight, and a town is located 6 mile
Alisiya [41]

Answer: 3.94 hours

Step-by-step explanation:

From the question, the following parameters are given:

Distance offshore = 4.5 miles

Distance downshore = 6 miles

Speed when running = 3.4 mph

Speed with boat = 1.8 mph

distance of boat rowing = sqrt(4.5^2 + x^2)

Where

Speed = distance/time

Time = distance/speed

Time = distance of boat rowing/1.8

distance of running = 6 - x

Time = (6-x)/3.4

total travel time

t = sqrt(4.5^2 + x^2)/1.8 + (6 - x)/3.4

dt/dx = x/(1.8×sqrt(4.5^2 + x^2) - 1/3.4

d^2t/dx^2 = +ve at any x

x is at its minimum when dt/dx=0

x/(1.8×sqrt(4.5^2 + x^2) = 1/3.4

x = 6/sqrt(253) × 4.5 = 1.697 miles

Substitute x in

t = sqrt(4.5^2 + x^2)/1.8 + (6 - x)/3.4

We obtaine

t = sqrt(4.5^2 + 1.697^2)/1.8 + (6 - 1.69)/3.4

t = 2.672+ 1.266 = 3.94 hours

7 0
3 years ago
Need help (midpoints)
Zinaida [17]

Answer:

5

Step-by-step explanation:

i know it

5 0
3 years ago
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