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3 years ago

If xvaries directly as y.x=5 and y=10. find theValue of a x when y=3

Mathematics

1 answer:

Serggg [28]3 years ago

4 0

Answer:

x = 1.5 when y = 3

Step-by-step explanation:

You can put this in a ratio:

x : y

5 : 10

1.5 : 3

x is 1.5 when y is 3.

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2 years ago

Professor wonders whether a student's homework average (X) could be used to predict their final grade in the course (Y) . She ca

Anna11 [10]

Answer:

The dependent variable is the final grade in the course and is the vriable of interest on this case.

H0: $\beta_1 = 0$

H1: $\beta_1 \neq 0$

And if we reject the null hypothesis we can conclude that we have a significant relationship between the two variables analyzed.

Step-by-step explanation:

On this case w ehave the following linear model:

$Y= 21.839 +0.724 X$

Where Y represent the final grade in the course and X the student's homework average. For this linear model the slope is given by $\beta_1 = 0.724$ and the intercept is $\beta_0 = 21.839$

Which is the dependent variable, and why?

The dependent variable is the final grade in the course and is the vriable of interest on this case.

Based on the material taught in this course, which of the following is the most appropriate alternative hypothesis to use for resolving this question?

Since we conduct a regression the hypothesis of interest are:

H0: $\beta_1 = 0$

H1: $\beta_1 \neq 0$

And if we reject the null hypothesis we can conclude that we have a significant relationship between the two variables analyzed.

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2 years ago

Write a quadratic function to model the vertical motion for each situation, given h(t) equals negative 16t squared plus v0t+h0

Mashcka [7]

Answer:

hmax = 194 ft

The maximum height is 194 ft

Step-by-step explanation:

According to the given equation for the model of the vertical motion. The height at any point in time can be written as;

h(t) = -16t^2 + v0t + h0 .......1

Where;

h(t) = height at time t

t = time

v0 = initial velocity = 96 ft/s

h0 = initial height = 50 ft

To determine the maximum height we need to differentiate the equation 1 to find the time at which it reaches maximum height;

At the highest point/height h' = dh/dt = 0

h'(t) = -32t +v0 = 0

-32t + v0 = 0

t = v0/32

t = 96/32

t = 3 s

At t=3 it is at maximum height.

The maximum height can be derived from equation 1;

Substituting the values of t,v0,h0 into equation 1;

h(t) = -16t^2 + v0t + h0 .......1

hmax = -16(3)^2 + 96(3) + 50 = 194 ft

hmax = 194 ft

The maximum height is 194 ft

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3 years ago

Find the common factor of all the terms of the polynomial 16x2 - 14x. A. 4x² B. 2x² c. 4x D. 2x

Harrizon [31]

Common factor would be D. 2x

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2 years ago

If xvaries directly as y.x=5 and y=10. find theValue of a x when y=3​

If xvaries directly as y.x=5 and y=10. find theValue of a x when y=3