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3 years ago

What mass of h2o will be produced if 9.5 g of h2 reacts with 1.2 g of o2?

1 answer:

7 0

Answer is: mass of water is 1,35 grams.
Chemical reaction: 2H₂ + O₂ → 2H₂O.
m(H₂) = 9,5 g.
n(H₂) = m(H₂) ÷ M(H₂).
n(H₂) = 9,5 g ÷ 2 g/mol.
n(H₂) = 4,75 mol.
m(O₂) = 1,2 g.
n(O₂) = 1,2 g ÷ 32 g/mol.
n(O₂) = 0,0375 mol; limiting reactant.
From chemical reaction: n(O₂) : n(H₂O) = 1 : 2.
n(H₂O) = 0,0375 mol · 2 = 0,075 mol.
m(H₂O) = 0,075 mol · 18 g/mol.
m(H₂O) = 1,35 g.

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A particular voltaic cell operates with the reaction: Zn(s)+Cl2(g)--->Zn^2+(aq)+2Cl^-(aq) giving a cell potential of .853 V.

nadya68 [22]

Answer:

The amount of energy liberated will be 49.38 J.

Explanation:

The amount of energy liberated (gibbs free energy) can be calculated using the following equation:

ΔG° = -nFε

n: amount of moles of electrons transfered

F: Faraday's constant

ε: cell potential

20.0 g of Zn is equal to 0.30 mol.

Two electrons are transfered during the reaction.

Therefore, n = 2x0.30 ∴ n = 0.60

ΔG° = - 0.60 x 96.485 x 0.853

ΔG° = 49.38 J

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4 years ago

How does the type of liquid used to make ice cubes affect the rate at which it melts?

3241004551 [841]

It doesn’t affect it

5 0

3 years ago

The overall cell reaction occurring in an alkaline battery isZn(s) + MnO₂(s) + H₂O(l) → ZnO(s) + Mn(OH)₂(s) (e) In practice, vol

zubka84 [21]

b) Mass of MnO₂ = 5.981 g

Mass of H₂O = 1.2384 g

c) Total Mass of Reactant consumed = 11.708 g

b) Given Reaction

Zn(s) + MnO₂(s) + H₂O(l) → ZnO(s) + Mn(OH)₂(s)

Mass of Zn = 4.50 g

Moles of Zn = 0.0688 moles

Now,

Moles of Zn = moles of MnO₂ = moles of H₂O = moles of ZnO = moles of Mn(OH)₂

Hence ,

Moles of MnO₂ = 0.0688 moles

Mass of MnO₂ = 0.0688 × 86.9368 g

= 5.981 g

Similarly,

Moles of H₂O = 0.0688 moles

Mass of H₂O = 0.0688 × 18 g

= 1.2384 g

c) now ,

Moles of ZnO = 0.0688 moles

Mass of ZnO = 0.06880× 81.3794 g

= 5.598 g

Moles of Mn(OH)₂ = 0.0688 moles

Mass of Mn(OH)₂ =0.0688 × 88.952 g

= 6.11 g

Total mass of Product = 11.708 g

Total Mass of Reactant = 11.715 g

Hence,

Total mass of reactant consumed = 11.708 g

c) As total mass of reactant is more than that of mass of reactant consumed , Hence G is more than that of mass of reactant consumed .

G = - nFEcell

and no. of moles of reactant is greater than that of number of moles of reactant consumed .

Hence voltaic cell of given Capacity are heavier than that of mass of reactant consumed .

Thus from above conclusion we can say that , Mass of the reactant consumed is 11.708 g.

Learn more about Galvanic Cell here : brainly.com/question/19340007

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3 0

2 years ago

Consider the following reaction and situations 1 through 10. In the spaces provided, clearly indicate the best response to each

olchik [2.2K]

Answer:

1. C. no change

2. A. increase

3. E. shift to the right

4. A. increase

5. E. shift to the right

6. A. increase

7. F. cannot be determined

8. B increase

9. D. shift to the left

10 F. cannot be determined

Explanation:

<em>According to Le Chaterlier principle, when a reaction is in equilibrium and one of the constraints that affect reactions is applied, the equilibrium will shift so as annul the effects of the constraints.</em>

From the equation: C(s) + H2O(g) ⇌ CO(g) + H2(g),

H is greater than 0, meaning that the system is endothermic, that is energy is absorbed.

1. If the pressure of the system is increased, there would be no change to the system because there are equal number of moles of products and reactants.

2. If H2 concentration is decreased, the equilibrium will shift to the right and more products will be formed. Hence, the concentration of CO will increase.

3. If H2 concentration is decreased, the equilibrium will shift to the right to annul the effects of the decrease in the concentration of a product.

4. If the concentration of H2 is increased, the equilibrium will shift to the left to annul the effects of increased concentration of a product. Hence, more H2O would be formed.

5. If H2 (a product) is removed, and C (a reactant) is added, more of the products will be formed in order to annul the effects of the actions. Hence, equilibrium will shift to the right.

6. If the amount of C (a reactant) is increased, the equilibrium will shift to the right. Hence, more H2 will be formed.

7. The reaction is endothermic, hence an increase in temperature will ordinarily shift the equilibrium to the right. However, the addition of H2 (a product) is supposed to shift the equilibrium to the left. Hence, the effects of simultaneous addition of the two actions become indeterminate.

8. Since the reaction is endothermic, increase in the temperature of the system will shift the equilibrium to the right. Hence, more CO will be formed.

9. If the concentration of H2O (a reactant) is decreased and that of CO (a product) is increased, both actions lead to the equilibrium being shifted to the left.

10. Addition of catalyst to the system will only speed up the rate at which the system reach the equilibrium.

5 0

3 years ago

A is a d-aldohexose and B is an L-aldohexose. they afford the same optically active aldaric acid after dilute nitric acid oxidat

Alexeev081 [22]

Answer:

D-Glucose and L-Glucose

Explanation:

Aldohexose are the sugars which have six number of carbons and ends up in having an aldehyde group at one end. When dilute nitric acid is treated with any of them, the molecule gets oxidized (gets oxygen) and therefore turns into carboxylic acid.

The name of A is D-Glucose, and B is L-Glucose. Please find the structural formula attached.

8 0

3 years ago

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