Answer:
Q = 63.75J
Explanation:
Mass = 2.5g
Initial temperature (T1) = 25°C
Final temperature (T2) = 50°C
Specific heat capacity of Mg = 1.020J/g°C
Heat energy = ?
Heat Energy (Q) = mc∇T
Q = heat energy
M = mass of substance
C = specific heat capacity of substance
∇T = change in temperature = T2 - T1
Q = mc∇T
Q = mc(T2 - T1)
Q = 2.5 × 1.020 × (50 - 25)
Q = 2.55 × 25
Q = 63.75J
The heat energy required to raise magnesium metal from 25°C to 50°C is 63.75J
Answer:
X liters of 10% + (30 - x) liters of 22% = 30...
Hello!
For this problem, we will be applying <em>Charles' Law</em>:
V1/T1 = V2/T2
Now that we have the formula, let's convert the temperature to Kelvin.
27 + 273 = 300K
Let's plug everything in now!
10/300 = 12.0/x
Simplified:
1/30 = 12.0/x
Cross-multiply:
1x = 30*12.0
<u>x = 360</u>
<em>Check!</em>
10/300 = 12/360
300*12 = 360*10
3600 = 3600
Therefore, you would have to heat the gas at a temperature of 360K in order to raise the volume to 12.0L.
