Detection of nitrogen and sulphur
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The 0.25 volume in liters of 1.0 M solution is required to provide 0.5 moles of
(aq).
Calculation,
The Potassium carbonate dissolves as follows:
→
The mole ratio is 1: 2
It means, the 1 mole required to form 2 mole of
(aq).
To provide 0.5 mole of (aq) = 1 mole ×0.5 mole /2 mole required by
.
To provide 0.5 mole of (aq) ,0.25 mole required by
.
The morality of = 1 M = number of moles / volume in lit
The morality of = 1 M = 0.25 mole/ volume in lit
Volume in lit = 0.25 mole / 1 M = 0.25 mole/mole/lit = 0.25 lit
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