<span>he accelerates when he runs away from home plate. as he reaches each base, the player accelerates by changing direction. he accelerates again when slowing down after reaching home plate.</span>
Answer:
19.8m/s
Explanation:
Given parameters:
Mass of the ball = 10kg
Height of the rail = 20m
Unknown:
Velocity at the bottom of the rail = ?
Solution:
The velocity at the bottom of the rail is its final velocity.
Using the appropriate motion equation, we can find this parameter;
V² = U² + 2gH
V is the final velocity
U is the initial velocity
g is the acceleration due to gravity
H is the height
the ball was rolled from rest, U = 0
V² = O² + 2 x 9.8 x 20
V = 19.8m/s
Are there answer choices or is this a write in answer?
Answer:
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