All categories

3 years ago

How do the leathery pads on the bottom of camel's feet help a camel? It is for a web quest thing

Chemistry

1 answer:

alisha [4.7K]3 years ago

8 0

The leathery pad helps the camel because it prevents the camels feet from sinking into the sand.

You might be interested in

A piece of wood that measures 2.7 cm x 5.5 cm x 3.9 cm has a mass of 84 g what is the density of the wood

Korolek [52]

The density of the wood : 1.45 g/cm³

<h3>Further explanation </h3>

Density is a quantity derived from the mass and volume

Density is the ratio of mass per unit volume

With the same mass, the volume of objects that have a high density will be smaller than objects with a smaller type of density

The unit of density can be expressed in g/cm³ or kg/m³

Density formula:

$\large {\boxed {\bold {\rho ~ = ~ \frac {m} {V}}}}$

ρ = density

m = mass

v = volume

Volume of the wood

$\tt V=2.7\times 5.5\times 3.9=57.915~cm^3$

density

$\tt \rho=\dfrac{m}{V}\\\\\rho=\dfrac{84~g}{57.915~cm^3}=\boxed{\bold{1.45`g/cm^3}}$

6 0

2 years ago

The rate of evaporation is affected by all of the following except

lidiya [134]

Hello there.

The rate of evaporation is affected by all of the following except

Answer: B. the humidity.

8 0

3 years ago

Read 2 more answers

What is an individual living entity called?

Citrus2011 [14]

Answer:

it is organism the third one

4 0

2 years ago

Read 2 more answers

What is the lowest temperature that a subtance can reach

Damm [24]

Answer: Theoretically: Absolute Zero

Explanation:

which is about -273.15 degrees Celsius

3 0

2 years ago

A 1.00 kg sample of Sb2S3 (s) and a 10.0 g sample of H2 (g) are allowed to react in a 25.0 L container at 713 K. At equilibrium,

Scorpion4ik [409]

Answer: The value of $K_c$ is coming out to be 0.412

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

For $Sb_2S_3$

Given mass of $Sb_2S_3$ = 1.00 kg = 1000 g (Conversion factor: 1 kg = 1000 g)

Molar mass of $Sb_2S_3$ = 339.7 g/mol

Putting values in equation 1, we get:

$\text{Moles of }Sb_2S_3=\frac{1000g}{339.7g/mol}=2.944mol$

For hydrogen gas:

Given mass of hydrogen gas = 10.0 g

Molar mass of hydrogen gas = 2 g/mol

Putting values in equation 1, we get:

$\text{Moles of hydrogen gas}=\frac{10.0g}{2g/mol}=5mol$

For hydrogen sulfide:

Given mass of hydrogen sulfide = 72.6 g

Molar mass of hydrogen sulfide = 34 g/mol

Putting values in equation 1, we get:

$\text{Moles of hydrogen sulfide}=\frac{72.6g}{34g/mol}=2.135mol$

The chemical equation for the reaction of antimony sulfide and hydrogen gas follows:

$Sb_2S_3(s)+3H_2(g)\rightarrow 2Sb(s)+3H_2S(g)$

Initial: 2.944 5

At eqllm: 2.944-x 5-3x 2x 3x

We are given:

Equilibrium moles of hydrogen sulfide = 2.135 moles

Calculating for 'x', we get:

$\Rightarrow 3x=2.135\\\\\Rightarrow x=\frac{2.135}{3}=0.712$

Equilibrium moles of hydrogen gas = (5 - 3x) = (5 - 3(0.712)) = 2.868 moles

Volume of the container = 25.0 L

Molarity of a solution is calculated by using the formula:

$\text{Molarity}=\frac{\text{Moles}}{\text{Volume}}$

The expression of $K_c$ for above equation, we get:

$K_c=\frac{[H_2S]^3}{[H_2]^3}$

The concentration of solids and liquids are not taken in the expression of equilibrium constant.

$K_c=\frac{(\frac{2.135}{25})^3}{(\frac{2.868}{25})^3}\\\\K_c=0.412$

Hence, the value of $K_c$ is coming out to be 0.412

3 0

3 years ago