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Zepler [3.9K]
3 years ago
13

Please answer correctly. No links please. How many pounds are there in 1.53 tons

Chemistry
1 answer:
Lana71 [14]3 years ago
6 0

Answer:

3060 lbs

Explanation:

multiply mass by 2000

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What is the amount in grams of EDTA needed to make 315.1 mL of a 0.05 M EDTA solution. The molar mass of EDTA is 374 g/mol
statuscvo [17]

Answer:

58.92 g EDTA

Explanation:

315.1 mL = .3151 L    

M = Moles / Liter

.3151 L  x <u>0.5 mol EDTA</u>  x  <u>374 g EDTA</u>  =  58.92 g EDTA

                1 L EDTA             1 mol EDTA

4 0
2 years ago
Ratio of nitrogen gas to helium
GarryVolchara [31]

Answer:

1 to 696

The expansion ratio of liquefied and cryogenic from the boiling point to ambient is: nitrogen 1 to 696. liquid helium 1 to 757. argon 1 to 847.

Explanation:

4 0
3 years ago
What is the density(in g/L) of a gas with a molar mass of 32.49g/mol at 2.569atm and 458K?
garri49 [273]

Answer:

2.22~g/L

Explanation:

According to the ideal gas law equation:

pV = nRT

Let's express the number of moles in terms of mass and molar mass:

pV = \frac{m}{M} RT

Let's divide both sides by volume:

p = \frac{m}{MV} RT

Notice that:

\frac{m}{V} = d

So the equation becomes:

p = \frac{dRT}{M}

Expressing density:

d = \frac{pM}{RT}

Substituting the given values:

d = \frac{2.569~atm\cdot 32.49~g/mol}{0.08206~\frac{L~atm}{mol~K}\cdot 458~K} = 2.22~g/L

7 0
4 years ago
Question:
guajiro [1.7K]

Answer:

What?

Explanation:

6 0
3 years ago
A) The equilibrium between carbon dioxide gas and carbonic acid is very important in biology and environmental science.
Vladimir [108]

Answer:

Explanation:

CO₂ (aq) + H₂O (l)   ⇄   H₂CO₃ (aq)

Equilibrium constant

Kc  =   [H₂CO₃] / [CO₂] [H₂O]

B )

PCl₃(g) + Cl₂(g)    <-->   PCl₅(g)

Kc = 24.3 .

[PCl₃] = .10M ,

[Cl₂] = 0.15 M

[PCl₅]  = 0.60 M.

Qc =  [PCl₅]  /  [PCl₃] [Cl₂]

= .60 / .10 x .15

= 40

Qc > Kc

Hence the reaction will proceed from left to right to reach equilibrium . It is so because the product concentration is more .

Option C is the right choice .

4 0
4 years ago
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