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AfilCa [17]
3 years ago
7

Fredrick is doing a lab on pH. He uses many household items to determine the pH of his items. Which of his actions best describe

s inappropriate lab safety?
He changes into closed-toed shoes before lab starts.
He doesn’t wear goggles because he is using household chemicals.
He asks his teacher if he can mix high- and low-pH solutions before discarding them.
He leaves his workstation to identify all of the safety equipment in the lab.
Chemistry
2 answers:
Oksana_A [137]3 years ago
4 0

The correct answer is B. He doesn’t wear goggles because he is using household chemicals.

Explanation:

Carrying out experiments especially those that imply substances such as chemicals implies following practices to guarantee safety. Because of this, in the lab you should use special clothes this includes goggles and gloves; you should clean and decontaminate your station; avoid eating, drinking or smoking and always ask your teacher for any step or procedure. This implies, the inappropriate action is "He doesn’t wear goggles because he is using household chemicals", because protection should be used all the time as even substance we use every day can be dangerous if you are closely exposed to them or if they are mixed with others.

NNADVOKAT [17]3 years ago
3 0

The correct answer is A.

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What is the maximum mass of ammonia that can be formed when 36.52 grams of nitrogen gas reacts with 10.62 grams of hydrogen gas
k0ka [10]

The maximum mass of NH₃ that can be formed when 36.52 g of N₂ reacts with 10.62 g of H₂ is 44.35 g

<h3>Balanced equation </h3>

N₂ + 3H₂ —> 2NH₃

Molar mass of N₂ = 14 × 2 = 28 g/mol

Mass of N₂ from the balanced equation = 1 × 28 = 28 g

Molar mass of H₂ = 2 × 1 = 2 g/mol

Mass of H₂ from the balanced equation = 3 × 2 = 6 g

Molar mass of NH₃ = 14 + (3×1) = 17 g/mol

Mass of NH₃ from the balanced equation = 2 × 17 = 34 g

SUMMARY

From the balanced equation above,

28 g of N₂ reacted with 6 g of H₂ to produce 34 g of NH₃

<h3>How to determine the limiting reactant </h3>

From the balanced equation above,

28 g of N₂ reacted with 6 g of H₂

Therefore,

36.52 g of N₂ will react with = (36.52 × 6) / 28 = 7.83 g of H₂

From the above calculation, we can see that only 7.83 g out of 10.62 g of H₂ are required to react completely with 36.52 g of N₂.

Therefore, N₂ is the limiting reactant

<h3>How to determine the maximum mass of NH₃ produced </h3>

From the balanced equation above,

28 g of N₂ reacted to produce 34 g of NH₃

Therefore,

36.52 g of N₂ will react to produce = (36.52 × 34) / 28 = 44.35 g of NH₃

Thus, the maximum mass of NH₃ obtained from the reaction is 44.35 g

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2 years ago
Calculate the mass percent of ba(no3)2 in this solution, assuming the density of the solution is 1.000 kg/l.
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You forgot to include the known characteristics of the solution.

I searched them and copy here:

volume: 1.000 liter

M = 0.0190 M

Now, you can start with the definition of mass percent.

mass percent = (grams of solute / grams of solution) * 100

grams of solute are obtained from the molar concentration:

M = (number of moles of solute) / (volume of solution in liters)

where number of moles = (grams) / (molar mass)

=> M = (grams of solute / molar mass of solute) / (volume of solution in liters)

=> grams of solute = M * (volume of solution in liters) * (molar mass of solute)

And density = (kg of solution / volume of solution in liters) =>

kg of solution = density * volume of solution in liters

grams of solution = density * (volume of solution in liters) * 1000 g/kg

=> mass percent = M * (volume of solution in liters) * (molar mass) / (density * volume of solution in liters * 1000 g/ kg) * 100

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now replace the values known:

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=> mass percent = 0.0190 mol/liter * 256.335 g/mol * 10  kg/ g / (1.000 kg/liter)

=> mass percent = 48.7%
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