The sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec
<h3>Calculating wavelength </h3>
From the question, we are to determine how many times longer is the first sound wave compared to the second sound water
Using the formula,
v = fλ
∴ λ = v/f
Where v is the velocity
f is the frequency
and λ is the wavelength
For the first wave
f = 20 waves/sec
Then,
λ₁ = v/20
For the second wave
f = 16,000 waves/sec
λ₂ = v/16000
Then,
The factor by which the first sound wave is longer than the second sound wave is
λ₁/ λ₂ = (v/20) ÷( v/16000)
= (v/20) × 16000/v)
= 16000/20
= 800
Hence, the sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec
Learn more on Calculating wavelength here: brainly.com/question/16396485
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Answer:
g(x) = 2(x - 2)^2 + 2 plot (see attachment)
Step-by-step explanation:
Answer:
10
Step-by-step explanation:
(2/3) x (15)
is the same as
(2/3) x (15/1)
which means after you multiply them you get:
30/3
which simplifies to:
10
The total travelled for the first five hours eould be 450 km and divided by three leaves 150 km per 1/5 of his journey. travelling at 75 km per hour, it would take 4 hours to get through the remaining 300 km for him trip leaving a total time of 9 hours of traveling
Answer:
(s*t)(-7) = 987
Step-by-step explanation:
s(x) = 2 - x²
t(x) = 3x
To find (s*t)(x), multiply s(x) and t(x).
(s*t)(x) = (2 - x²)(3x)
(s*t)(x) = 6x - 3x³
Now that you have (s*t)(x), plug -7 in.
(s*t)(-7) = 6(-7) - 3(-7)³
(s*t)(-7) = 6(-7) - 3(-343)
(s*t)(-7) = -42 + 1029
(s*t)(-7) = 987
