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Bingel [31]
3 years ago
9

Okay have posted the next question.

Mathematics
2 answers:
Verdich [7]3 years ago
8 0

Answer:

1. only 1 unique triangle can be made

2. only 1 unique triangle can be made

3. multiple triangles are possible

4. True

5. True

6. False

7. only 1 unique triangle can be made

8. only 1 unique triangle is possible

9. multiple triangles are possible

10. no triangle is possible

Step-by-step explanation:

Ask in comments if you got any questions.

Trava [24]3 years ago
5 0

Answer:All are correct I think.

Step-by-step explanation:

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Similarity in right triangles. Find the value of X. 
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Answer:

70

Step-by-step explanation:

Using the similarity theorem;

AB/BC = AD/AB

x/7+3 = 7/x

x/10 = 7/x

x^2 = 70

x = √70

Hence the required value inside square root is 70

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andreyandreev [35.5K]

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3 years ago
Determine whether each of the following functions is a solution of laplace's equation uxx uyy = 0.
ratelena [41]

Both functions are the solution to the given Laplace solution.

Given Laplace's equation: u_{x x}+u_{y y}=0

  • We must determine whether a given function is the solution to a given Laplace equation.
  • If a function is a solution to a given Laplace's equation, it satisfies the solution.

(1) u=e^{-x} \cos y-e^{-y} \cos x

Differentiate with respect to x as follows:

u_x=-e^{-x} \cos y+e^{-y} \sin x\\u_{x x}=e^{-x} \cos y+e^{-y} \cos x

Differentiate with respect to y as follows:

u_{x x}=e^{-x} \cos y+e^{-y} \cos x\\u_{y y}=-e^{-x} \cos y-e^{-y} \cos x

Supplement the values in the given Laplace equation.

e^{-x} \cos y+e^{-y} \cos x-e^{-x} \cos y-e^{-y} \cos x=0

The given function in this case is the solution to the given Laplace equation.

(2) u=\sin x \cosh y+\cos x \sinh y

Differentiate with respect to x as follows:

u_x=\cos x \cosh y-\sin x \sinh y\\u_{x x}=-\sin x \cosh y-\cos x \sinh y

Differentiate with respect to y as follows:

u_y=\sin x \sinh y+\cos x \cosh y\\u_{y y}=\sin x \cosh y+\cos x \sinh y

Substitute the values to obtain:

-\sin x \cosh y-\cos x \sinh y+\sin x \cosh y+\cos x \sinh y=0
The given function in this case is the solution to the given Laplace equation.

Therefore, both functions are the solution to the given Laplace solution.

Know more about Laplace's equation here:

brainly.com/question/14040033

#SPJ4

The correct question is given below:
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6 0
2 years ago
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