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olga nikolaevna [1]
4 years ago
5

What is the difference between weight and mass

Physics
1 answer:
baherus [9]4 years ago
4 0
     Mass (m) is the amount of matter that the body has, measured in kilograms (kg) in the SI. Weight (P) is the force of attraction that a planet exerts on the body, meansured in Newton (N). The relationship between them is given by Definition of Weight:

P=mg~,~where~g=gravity

If you notice any mistake in my english, please let me know, because i am not native.
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Explain why pumice floats and why ironwood sinks
almond37 [142]

Answer:

A quick way of describing density is to describe an object as heavy or light for its size. Pumice stone, unlike regular rock, does not sink in water because it has a low density. An ironwood branch is very dense and sinks in water.

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A 1.65 kg mass stretches a vertical spring 0.260 m If the spring is stretched an additional 0.130 m and released, how long does
Irina-Kira [14]

Answer:

The system will take approximately 0.255 seconds to reach the (new) equilibrium position.

Explanation:

We notice that block-spring system depicts a Simple Harmonic Motion, whose equation of motion is:

y(t) = A\cdot \cos \left(\sqrt{\frac{k}{m} }\cdot t +\phi\right) (1)

Where:

y(t) - Position of the mass as a function of time, measured in meters.

A - Amplitude, measured in meters.

k - Spring constant, measured in newtons per meter.

m - Mass of the block, measured in kilograms.

t - Time, measured in seconds.

\phi - Phase, measured in radians.

The spring is now calculated by Hooke's Law, that is:

k = \frac{m\cdot g}{\Delta y} (2)

Where:

g - Gravitational acceleration, measured in meters per square second.

\Delta y - Deformation of the spring due to gravity, measured in meters.

If we know that m=1.65\,kg, g = 9.807\,\frac{m}{s^{2}} and \Delta y = 0.260\,m, then the spring constant is:

k = \frac{(1.65\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)}{0.260\,m}

k = 62.237\,\frac{N}{m}

If we know that A = 0.130\,m, k = 62.237\,\frac{N}{m}, m=1.65\,kg, x(t) = 0\,m and \phi = 0\,rad, then (1) is reduced into this form:

0.130\cdot \cos (6.142\cdot t)=0 (1)

And now we solve for t. Given that cosine is a periodic function, we are only interested in the least value of t such that mass reaches equilibrium position. Then:

\cos (6.142\cdot t) = 0

6.142\cdot t = \cos^{-1} 0

t = \frac{1}{6.142}\cdot \left(\frac{\pi}{2} \right)\,s

t \approx 0.255\,s

The system will take approximately 0.255 seconds to reach the (new) equilibrium position.

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3 years ago
Accorrding to Kepler's third law, a planet whose distance from the Sun is 2 A.U. would have an orbital period of how many Earth-
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Answer:

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Explanation:

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What is the intensity of a traveling plane electromagnetic wave?
abruzzese [7]
Your question seems incomplete, however, I might help you solve the problem even though the values are not given. The intensity of a traveling plane electromagnetic wave can be computed using the following equation:

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