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Ray Of Light [21]
1 year ago
8

which of the following statements best justifies the inclusion of test tube v as a control in the experiment? responses it will

provide a measurement of amylase activity at an acidic ph.
Physics
1 answer:
prohojiy [21]1 year ago
5 0

The following statement which best justifies the inclusion of test tube v as a control in the experiment is that it will show the color change that occurs in the absence of enzyme activity and is denoted as option C.

<h3>What is an Enzyme?</h3>

This is referred to as a biological catalyst which is involved in the speeding up of the rate of a reaction by lowering the activation energy used to initiate the reaction.

Enzymes are known as proteinous in nature and are denatured by heat and other substances is included in the test tube v as a control in the experiment is that it will show the color change that occurs in the absence of enzyme activity.

This therefore helps to differentiate the enzymatic processes which takes place in a substance or body therefore making option C the correct choice.

Read more about Enzyme here brainly.com/question/1596855

#SPJ1

The options are:

  • It will provide a measurement of amylase activity at an acidic pH.
  • it will provide a measurement of amylase activity at a basic pH.
  • It will show the color change that occurs in the absence of enzyme activity.
  • it will show the color change that occurs in the absence of the amylase protein.

It will show the color change that occurs in the absence of enzyme activity.

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3 0
3 years ago
1) How much work is done when a force of 50N<br> pulls a wagon 20 meters?
katrin2010 [14]

Answer:

100J

Explanation:

50N*20m=100J

N*m=J(joule)

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Which best describes how magnesium and oxygen bond?
Lostsunrise [7]

Answer:

They form an ionic bond by exchanging two electrons.

Explanation:

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3 years ago
Raul dug a hole in his yard to repair a water pipe. It took him 2 seconds to apply a force of 50 Newtons to push the shovel 0.25
Sergeu [11.5K]

Answer:

Option B. 6.25 J/S

Explanation:

Data obtained from the question include:

t (time) = 2secs

F (force) = 50N

d (distance) = 0.25m

P (power) =?

The power can be obtained by using the formula P = workdone/time.

P = workdone / time

P = (50 x 0.25)/ 2

P = 6.25J/s

3 0
3 years ago
A point charge q1 = is located at the center of a thick conducting spherical shell of inner radius a = 2.2 cm and outer radius b
Yanka [14]

Answer:

Ex(P) = -3.602 x 10^6 N/C

Explanation:

  • given q1 = -5.7μC
  • q2 = 2.6 μC = the net charge on the conducting shell
  • inner radius of conducting shell = a = 2.2 cm =0.022m
  • outer radius of conducting shell = b = 4.5 cm = 0.045m

1) To get Ex(P), the value of the x-component of the electric field at point P, located a distance 8.8 cm along the x-axis from q1 ;

Ex(P) = k(q1+q2)/r^2

= 9 x 10^9 (-5.7 + 2.6) x 10^-6 /0.088^2

Ex(P) = -27.9 x 10^3/ 0.007744

Ex(P) = -3.602 x 10^6 N/C

7 0
4 years ago
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