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3 years ago

SOMEONE PLEASE HELP ME WITH THIS MATH IM STRUGGLING!

Mathematics

1 answer:

NemiM [27]3 years ago

5 0

Answer:

I think 58'is right answer

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Find the slope of the line passing through (3,-1) and (6,4).

dybincka [34]

Answer:

The answer to your question is: m = 5/3

Step-by-step explanation:

Data

A (3, -1)

B (6, 4)

Formula

$m = \frac{y2 - y1 }{x2 - x1}$

Process

$m = \frac{4 + 1}{6 - 3}$

$m = \frac{5}{3}$

4 0

3 years ago

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Given the piece wise function shown below, select all of the statements that are true

allsm [11]

C and d

when x = 2 , f(x) = x^2 = 4
and
when x = 1 f(x) = 5

8 0

3 years ago

Match each expression in the left column with the correct product in the right column.

lesya692 [45]

Answer:

-6

-6i

Step-by-step explanation:

1) √4 . √-3 . √-3

$\sqrt{4} = 2$

$\sqrt{-3} . \sqrt{-3} = (\sqrt{-3})^2$

$\sqrt{4} . (\sqrt{-3})^2 = 2 \times -3 =$ -6

2) √-4 . √-3 . √-3

$\sqrt{-4} = 2i$ .

Therefore, $\sqrt{-4} . \sqrt{-3} . \sqrt{-3} = 2. \sqrt{-1} \times -3 = 2i \times (-3) =$ - 6i

3) √4 . √3 . √-3

$\sqrt{4} = 2$

$\sqrt{3} . \sqrt{-3} = (\sqrt{3})^2 . \sqrt{-1}$

$\implies 2 \times 3i =$ 6i

4) √4 . √3 . √3

$\sqrt{4} = 2$

$\sqrt{3} . \sqrt{3} = (\sqrt{3})^2 = 3$

Therefore, √4 . √3 . √3 = 2 . 3 = 6

5 0

3 years ago

14,494 ten thousand round to

SVETLANKA909090 [29]

"14,494 rounded to the nearest ten-thousands" would be 10,000.

Because the value of the digit before the ten thousands place (4) is less than the value of 5, the digit in the ten-thousands position does not change.

3 0

3 years ago

I need help, -3x+9+4x=10 just wondering if the answer is X=1

enyata [817]

Answer:

it's correct good job :)

5 0

3 years ago

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