All categories

3 years ago

What is the nth term rule of the linear sequence -5,-7,-9,-11,-13

Mathematics

2 answers:

RUDIKE [14]3 years ago

4 0

Your rule for the sequence is -2n-3. Substitute any value for n and you will get the input. Hopefully this helps

monitta3 years ago

3 0

Answer:

-7

Step-by-step explanation:

cause I took the test and got it right in my first try

You might be interested in

If angle 1 has a measure of 56° and angle 2 has a measure of 124°, the two angles are complementary.

Citrus2011 [14]

Answer:

False.

Step-by-step explanation:

Two angles are complementary when added up, they give a result of 90°.

So, to this question to be true we have to do:

Angle 1 + Angle 2 = 90

But if we resolve 56° + 124° = 180, so this means that this question is false, as the addition of both angles doesn't have a result of 90°.

8 0

3 years ago

Problem: 2x+3 (x-4)=x-20

monitta

Let's solve your equation step-by-step.2x+3(x−4)=x−20Step 1: Simplify both sides of the equation.2x+3(x−4)=x−20Simplify: (Show steps)5x−12=x−20Step 2: Subtract x from both sides.5x−12−x=x−20−x4x−12=−20Step 3: Add 12 to both sides.4x−12+12=−20+124x=−8Step 4: Divide both sides by 4.4x/4=−8/4x=−2Answer: x=−2

6 0

3 years ago

Solve each proportion

mamaluj [8]

Hello.

In order to solve a proportion, you should cross-multiply:

$\displaystyle\frac{7}{x} =\frac{5}{9}$

Multiply 7 times 9 and 5 times x:

5x=63

Divide both sides by 5:

x= $\displaystyle\frac{63}{5}$

Now let's solve the second proportion.

Multiply 8p times 6 and 12 times 15:

48p=180

Divide both sides by 48:

p=3.75

I hope it helps.

Have an outstanding day.

$\boxed{imperturbability}$

5 0

2 years ago

6x +8=5x=4 what is the value of x

Free_Kalibri [48]

Answer:

x = -4/11

Step-by-step explanation:

add the x values.

11x+8=4

subtract 8 from each sides

11x=-4

divide by 11

x=-4/11

8 0

3 years ago

It appears that people who are mildly obese are less active than leaner people. One study looked at the average number of minute

hoa [83]

Answer:

Obese people

$Lower = \mu - 2\sigma = 373- 2(67) = 239$

$Upper = \mu + 2\sigma = 373+ 2(67) = 507$

Lean People

$Lower = \mu - 2\sigma = 526- 2(107) = 312$

$Upper = \mu + 2\sigma = 526+ 2(107) = 740$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

The empirical rule, also referred to as the three-sigma rule or 68-95-99.7 rule, is a statistical rule which states that for a normal distribution, "almost all data falls within three standard deviations (denoted by σ) of the mean (denoted by µ). Broken down, the empirical rule shows that 68% falls within the first standard deviation (µ ± σ), 95% within the first two standard deviations (µ ± 2σ), and 99.7% within the first three standard deviations (µ ± 3σ)".

Solution to the problem

Obese people

Let X the random variable that represent the minutes of a population (obese people), and for this case we know the distribution for X is given by:

$X \sim N(373,67)$

Where $\mu=373$ and $\sigma=67$

On this case we know that 95% of the data values are within two deviation from the mean using the 68-95-99.7 rule so then we can find the limits liek this:

$Lower = \mu - 2\sigma = 373- 2(67) = 239$

$Upper = \mu + 2\sigma = 373+ 2(67) = 507$

Lean People

Let X the random variable that represent the minutes of a population (lean people), and for this case we know the distribution for X is given by:

$X \sim N(526,107)$

Where $\mu=526$ and $\sigma=107$

On this case we know that 95% of the data values are within two deviation from the mean using the 68-95-99.7 rule so then we can find the limits liek this:

$Lower = \mu - 2\sigma = 526- 2(107) = 312$

$Upper = \mu + 2\sigma = 526+ 2(107) = 740$

The interval for the lean people is significantly higher than the interval for the obese people.

5 0

3 years ago