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Colt1911 [192]
3 years ago
6

A golf retailer purchases its clubs from a wholesaler at $38 per club. It sells the same clubs to golfers at $72 per club. What

is the markup on each club, as a percentage of the wholesale price?
Mathematics
1 answer:
igor_vitrenko [27]3 years ago
6 0

Answer:47%

Step-by-step explanation:

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Find the equivalent expressions for (2+7)(x+1).
solong [7]
9x1

You would add 2+7 which =9 then x+1 that’s 1 so it would be 9x1
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Can someone help me with my math please?
LUCKY_DIMON [66]

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Step-by-step explanation:

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5j+16−12(−9j−4)=12j show steps
Triss [41]

Answer:  j = - 64 / 101

Step-by-step explanation:

5

7 0
3 years ago
Given w1 = -2 + 3i and W2 = 4 - 4i, which complex number can be added to Wi to produce wz?
lyudmila [28]

Given:

Two complex numbers are w_1=-2+3i and w_2=4-4i.

To find:

The complex number that can be added to w_1 to produce w_2.

Solution:

Let complex number z= is added to w_1 to produce w_2.

w_1+z=w_2

z=w_2-w_1

On substituting the values, we get

z=(4-4i)-(-2+3i)

z=4-4i+2-3i

Combine like real and imaginary parts.

z=(4+2)+(-4-3)i

z=6+(-7)i

z=6-7i

Therefore, the correct option is C.

4 0
3 years ago
Let the region R be the area enclosed by the function f(x)=ln(x) and g(x)= 1/2x-2. Find the volume of the solid generated when t
Neporo4naja [7]

Answer:

V=61.66

Step-by-step explanation:

This problem can be solved by using the expression for the Volume of a solid with the washer method

V=\pi \int \limit_a^b[R(x)^2-r(x)^2]dx

where R and r are the functions f and g respectively (f for the upper bound of the region and r for the lower bound).

Before we have to compute the limits of the integral. We can do that by taking f=g, that is

f(x)=g(x)\\ln(x)=\frac{1}{2}x-2

there are two point of intersection (that have been calculated with a software program as Wolfram alpha, because there is no way to solve analiticaly)

x1=0.14

x2=8.21

and because the revolution is around y=-5 we have

R=ln(x)-(-5)\\r=\frac{1}{2}x-2-(-5)\\

and by replacing in the integral we have

V=\pi \int \limit_{x1}^{x2}[(lnx+5)^2-(\frac{1}{2}x+3)^2]dx\\

V=\pi [28x+\frac{1}{x}+xln^2x-12xlnx-6lnx]  

and by evaluating in the limits we have

V=61.66

Hope this helps

regards

3 0
3 years ago
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