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Tom [10]
2 years ago
12

Determine f(-a) where f(x) = x2 - 6x and simplify.

Mathematics
1 answer:
jeka57 [31]2 years ago
5 0

Answer:

6a

Step-by-step explanation:

replace x with -a

-2a -6(-a)

-2a +8a

6a

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Factor. x^2+7x-30 <br> Please show me the answer please
jeka57 [31]

Answer:

(x-3) (x+10)

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
8. Expand, then simplify: (2 Points) (2a – 3) (a2 + 3a - 5) ​
MA_775_DIABLO [31]

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3 0
3 years ago
The sum of two polynomials is 10a^2b^2-8a^2b+6ab^2-4ab+2 if one addend is -5a^2b^2+12a^2b-5 what is the other addend
spayn [35]

Answer:

The other addend is 15\cdot a^{2}\cdot b^{2}-20\cdot a^{2}\cdot b + 6\cdot a \cdot b^{2}-4\cdot a \cdot b +7.

Step-by-step explanation:

The other addend is determined by subtracting -5\cdot a^{2}\cdot b^{2}+12\cdot a^{2}\cdot b-5 from 10\cdot a^{2}\cdot b^{2}-8\cdot a^{2}\cdot b + 6\cdot a\cdot b^{2}-4\cdot a \cdot b + 2:

x = 10\cdot a^{2}\cdot b^{2}-8\cdot a^{2}\cdot b + 6\cdot a \cdot b^{2}-4\cdot a \cdot b + 2 - (-5\cdot a^{2}\cdot b^{2}+12\cdot a^{2}\cdot b -5)

x = 10\cdot a^{2}\cdot b^{2}-8\cdot a^{2}\cdot b + 6\cdot a \cdot b^{2}-4\cdot a \cdot b +2 +5\cdot a^{2}\cdot b^{2}-12\cdot a^{2}\cdot b+5

x = (10\cdot a^{2}\cdot b^{2}+5\cdot a^{2}\cdot b^{2})-(8\cdot a^{2}\cdot b+12\cdot a^{2}\cdot b)+6\cdot a \cdot b^{2}-4\cdot a \cdot b +7

x = 15\cdot a^{2}\cdot b^{2}-20\cdot a^{2}\cdot b + 6\cdot a \cdot b^{2}-4\cdot a \cdot b +7

The other addend is 15\cdot a^{2}\cdot b^{2}-20\cdot a^{2}\cdot b + 6\cdot a \cdot b^{2}-4\cdot a \cdot b +7.

6 0
3 years ago
13p + 5p - 9p -2p=7 what is p
Law Incorporation [45]

Answer:

p=1

Step-by-step explanation:

18p-9p=9p

9p-2p=7p

7p=7

6 0
3 years ago
How do you do this?<br> Please help, I’ve been staring at this for like 10 min :)
damaskus [11]

Answer & Step-by-step explanation:

The formula is given in the middle. You are supposed to insert the value of x into this formula to find the value of y (like in the first given example):

x=-2\\y=2(-2)+5\\y=-4+5\\y=1

------

x=-1\\y=2(-1)+5\\y=-2+5\\y=3

------

x=0\\y=2(0)+5\\y=0+5\\y=5

------

x=1\\y=2(1)+5\\y=2+5\\y=7

------

x=2\\y=2(2)+5\\y=4+5\\y=9

:Done

3 0
3 years ago
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