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2 years ago

Determine f(-a) where f(x) = x2 - 6x and simplify.

Mathematics

1 answer:

jeka57 [31]2 years ago

5 0

Answer:

Step-by-step explanation:

replace x with -a

-2a -6(-a)

-2a +8a

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Factor. x^2+7x-30 <br> Please show me the answer please

jeka57 [31]

Answer:

(x-3) (x+10)

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

8. Expand, then simplify: (2 Points) (2a – 3) (a2 + 3a - 5)

MA_775_DIABLO [31]

Hello

just a second

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3 0

3 years ago

The sum of two polynomials is 10a^2b^2-8a^2b+6ab^2-4ab+2 if one addend is -5a^2b^2+12a^2b-5 what is the other addend

spayn [35]

Answer:

The other addend is $15\cdot a^{2}\cdot b^{2}-20\cdot a^{2}\cdot b + 6\cdot a \cdot b^{2}-4\cdot a \cdot b +7$ .

Step-by-step explanation:

The other addend is determined by subtracting $-5\cdot a^{2}\cdot b^{2}+12\cdot a^{2}\cdot b-5$ from $10\cdot a^{2}\cdot b^{2}-8\cdot a^{2}\cdot b + 6\cdot a\cdot b^{2}-4\cdot a \cdot b + 2$ :

$x = 10\cdot a^{2}\cdot b^{2}-8\cdot a^{2}\cdot b + 6\cdot a \cdot b^{2}-4\cdot a \cdot b + 2 - (-5\cdot a^{2}\cdot b^{2}+12\cdot a^{2}\cdot b -5)$

$x = 10\cdot a^{2}\cdot b^{2}-8\cdot a^{2}\cdot b + 6\cdot a \cdot b^{2}-4\cdot a \cdot b +2 +5\cdot a^{2}\cdot b^{2}-12\cdot a^{2}\cdot b+5$

$x = (10\cdot a^{2}\cdot b^{2}+5\cdot a^{2}\cdot b^{2})-(8\cdot a^{2}\cdot b+12\cdot a^{2}\cdot b)+6\cdot a \cdot b^{2}-4\cdot a \cdot b +7$

$x = 15\cdot a^{2}\cdot b^{2}-20\cdot a^{2}\cdot b + 6\cdot a \cdot b^{2}-4\cdot a \cdot b +7$

The other addend is $15\cdot a^{2}\cdot b^{2}-20\cdot a^{2}\cdot b + 6\cdot a \cdot b^{2}-4\cdot a \cdot b +7$ .

6 0

3 years ago

13p + 5p - 9p -2p=7 what is p

Law Incorporation [45]

Answer:

p=1

Step-by-step explanation:

18p-9p=9p

9p-2p=7p

7p=7

6 0

3 years ago

How do you do this?<br> Please help, I’ve been staring at this for like 10 min :)

damaskus [11]

Answer & Step-by-step explanation:

The formula is given in the middle. You are supposed to insert the value of x into this formula to find the value of y (like in the first given example):

$x=-2\\y=2(-2)+5\\y=-4+5\\y=1$

------

$x=-1\\y=2(-1)+5\\y=-2+5\\y=3$

------

$x=0\\y=2(0)+5\\y=0+5\\y=5$

------

$x=1\\y=2(1)+5\\y=2+5\\y=7$

------

$x=2\\y=2(2)+5\\y=4+5\\y=9$

:Done

3 0

3 years ago