Student made five tetrahedrons, a three dimensional figure with four triangular faces and labeled the faces 1-4. use an equation
to find the probability that all five tetrahedrons land on 3.
how do I do this? I don't understand please help
2 answers:
The probability is 1/1024.
Each tetrahedron has a 1/4 chance of landing on 3, since there are 4 sides and only one of them is marked 3.
Each tetrahedron roll is independent, since no roll is affected by another.
This means we multiply the probabilities:
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The probability is 1/1024.
Each tetrahedron has a 1/4 chance of landing on 3, since there are 4 sides and only one of them is marked 3.
Each tetrahedron roll is independent, since no roll is affected by another.
This means we multiply the probabilities:
1/4(1/4)(1/4)(1/4)(1/4) = 1/1024
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3.59
Or 3.593
Or 3.6
It matters what spot u want it reduced to
The probability would be 31/100.
The answer should be:
(x-4)^2 + (y+3)^2 = 6.25
hope this helped!
Answer:
(1,1)
Step-by-step explanation:
M=(x1+x2 / 2 , y1+y2 / 2)
M=(-2+4 / 2 , 4+ -2 / 2)
M=(2 / 2 , 2 / 2)
M=(1,1)
Answer:sorry i cant
Step-by-step explanation:
