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Mnenie [13.5K]
3 years ago
11

Student made five tetrahedrons, a three dimensional figure with four triangular faces and labeled the faces 1-4. use an equation

to find the probability that all five tetrahedrons land on 3.
how do I do this? I don't understand please help
Mathematics
2 answers:
alisha [4.7K]3 years ago
5 0

The probability is 1/1024.


Each tetrahedron has a 1/4 chance of landing on 3, since there are 4 sides and only one of them is marked 3.


Each tetrahedron roll is independent, since no roll is affected by another.


This means we multiply the probabilities:


Read more on Brainly.com - brainly.com/question/9984470#readmore

JulsSmile [24]3 years ago
3 0
The probability is 1/1024.

Each tetrahedron has a 1/4 chance of landing on 3, since there are 4 sides and only one of them is marked 3.

Each tetrahedron roll is independent, since no roll is affected by another.

This means we multiply the probabilities:
1/4(1/4)(1/4)(1/4)(1/4) = 1/1024
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Romashka [77]

Answer:

The answer is x = 5.

Step-by-step explanation:

Given:

Δ ABC is an Isosceles triangle with AB = CA

   m∠ ABC = ( 6x + 4 )°

   m∠ BAC = 73°

   m∠ BCA = ( 8y - 7 )°

To Find:

x = ?

Solution:

Properties of an Isosceles Triangle.

  1. Base angles or two angles are equal.
  2. Any two sides are equal.

Here , Δ ABC is an Isosceles triangle with AB = CA

∴  m∠ BAC = m∠ BCA

73= 8y-7\\8y=73+7\\8y=80\\y=\frac{80}{10} \\y=10

∴      m∠ BCA = ( 8y - 7 )°

                       = 8 × 10 - 7

       m∠ BCA  = 73  Which is same as ∠ CAB

Property of a Triangle is Sum of the measures of the angle of a triangle is 180°.

\angle ACB + \angle CAB + \angle CBA = 180

Substituting the values we get,

73 + 73 + (6x+4) = 180\\6x+4=180-146\\6x=34-4\\6x=30\\x=\frac{30}{6} \\x=5\\

The answer is x = 5.

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