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Mashcka [7]
3 years ago
15

PLEASE HELP!! THIS IS REALLY SERIOUS!!

Mathematics
1 answer:
Ivahew [28]3 years ago
8 0

Answer:

A. y= - 1/2x + 20

B. the initial value represents the total amount of gasoline used for snow plowing (in gallons)

C. the slope indicates that for every driveway plowed they use 1/2 a gallon of gasoline

hope this helps ;)

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50 POINTS! :D
Alexxandr [17]

Answer:

The speed of the first car is 60 mph

Step-by-step explanation:

speed = distance/time

Solve the above equation for distance to get

distance = speed * time

or simply

d = st

Now we use this formula for distance to write an equation for each car.

Let s = speed of second car

Then since the speed of the first car is 10 mph faster, the first car's speed is s + 10.

The time the two cars traveled is equal but unknown, so let the time = t.

First car: speed = s + 10; time = t; distance = 120 miles

d = st

120 = (s + 10)t    

(s + 10)t = 120      Equation 1

Second car: speed = s; time = t; 100 miles

d = st

100 = st

st = 100       Equation 2

Equations 1 and 2 form a system of 2 equations in 2 unknowns.

(s + 10)t = 120

st = 100

Distribute t in the first equation.

st + 10t = 120

From the second equation we know st = 100, so substitute 100 for st.

100 + 10t = 120

10t = 120

t = 2

The time traveled was 2 hours.

Equation 2:

st = 100

Substitute t with 2.

s * 2 = 100

s = 50

The speed of the second car was 50 mph.

The speed of the first car is s + 10.

s + 10 = 50 + 10 = 60

Answer: The speed of the first car is 60 mph

8 0
3 years ago
Verify the identity
Thepotemich [5.8K]

<u>Given</u>:

Given that we need to prove the identity \sin x+\sin x \tan ^{2} x=\tan x \sec x

<u>Proof</u>:

Step 1: Factor out the common term sin x, we get;

\sin x\left(1+\tan ^{2} x\right)=tan \ x \ sec \ x

Step 2: Using the identity 1+tan^2 x=sec^2x

\sin x \sec ^{2} x=tan \ x \ sec \ x

Step 3: Reciprocating sec x, we get;

\sin x \cdot \frac{1}{\cos ^{2} x}=tan \ x \ sec \ x

Step 4: Splitting the denominator, we have;

\frac{\sin x}{\cos x} \cdot \frac{1}{\cos x}=tan \ x \ sec \ x

Simplifying, we get;

\tan x \sec x=\tan x \sec x

Thus, the identity is proved.

5 0
3 years ago
Subtract -139.6 - 140.03
kobusy [5.1K]

Answer:

-279.63

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
What is the end behavior of the function <img src="https://tex.z-dn.net/?f=f%28x%29%3D-%5Cfrac%7B1%7D%7B4%7D%20x%5E2" id="TexFor
Anarel [89]

Answer:

<em><u>Option A </u></em>will be your answer

Step-by-step explanation:

<em><u>hope it helps </u></em><em><u>.</u></em><em><u>.</u></em>

<em><u>have</u></em><em><u> </u></em><em><u>a</u></em><em><u> </u></em><em><u>great</u></em><em><u> </u></em><em><u>day</u></em><em><u>!</u></em><em><u>!</u></em>

5 0
3 years ago
Use the following information for the question. Male players at the high school, college and professional ranks use a regulation
Virty [35]

Answer:

13.567%

Step-by-step explanation:

We solve the above question, using z score formula

z = (x-μ)/σ, where

x is the raw score = 23.1 ounces

μ is the population mean = 22.0 ounces

σ is the population standard deviation = 1.0 ounce

More than = Greater than with the sign = >

Hence, for x > 23.1 ounces

z = 23.1 - 22.0/1.0

= 1.1

Probability value from Z-Table:

P(x<23.1) = 0.86433

P(x>23.1) = 1 - P(x<23.1)

P(x>23.1) = 1 - 0.86433

P(x>23.1) = 0.13567

Converting to percentage

= 0.13567 × 100

= 13.567%

Therefore, the percentage of regulation basketballs that weigh more than 23.1 ounces is 13.567%

8 0
3 years ago
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