Let the required no. be x then according to question
(84/100)*x = 21
x = 21*(100/84)
x = 2100/84
x = 25
hence the required no. is 25
hope it helped
1.) Number of Total Shirts = 220
In Figure 1, Red boxes represent "<span>short sleeve shirts" which is 7 in number whereas Blue boxes represent "long sleeve shirts".
1 box contains = 220/10 = 22 shirts
Number of short sleeves = 22 * 7 = 154
<span>
In short, Your Final Answer would be: 154 </span></span>2.) Number of Total Subscribers = 260
In Figure 1, Red boxes represent "<span>regular subscribers" which is 10 in number whereas Blue boxes represent "premium subscribers".
1 box contains = 260/13 = 20 subscribers.
Regular subscribers = 20 * 10 = 200
<span>
In short, Your Final Answer would be: 200</span></span>
3.) Number of Total People = 360
In Figure 1, Red boxes represent "<span>Males" which is 3 in number whereas Blue boxes represent "females".
1 box contains = 360/12 = 30 people
Number of males: = 30 * 3 = 90
<span>
In short, Your Final Answer would be: 90
Hope this helps!</span></span>
Answer:
Step-by-step explanation:
Given that two fair dice are rolled 3 times and the sum of the numbers that come up is recorded.
a) The sum is 4 on each of the three rolls.
(1,3) (2,2) (3,1) HEnce for one throw prob = 3/36 =1/12
Prob for getting same sum 4 in 3 rolls = 
(since each trial is independent)
b) Prob sum =4 in exactly 2 rolls
=
=
Answer:
-4/8
Step-by-step explanation:
that's what my math says
Answer:
A(t) = 300 -260e^(-t/50)
Step-by-step explanation:
The rate of change of A(t) is ...
A'(t) = 6 -6/300·A(t)
Rewriting, we have ...
A'(t) +(1/50)A(t) = 6
This has solution ...
A(t) = p + qe^-(t/50)
We need to find the values of p and q. Using the differential equation, we ahve ...
A'(t) = -q/50e^-(t/50) = 6 - (p +qe^-(t/50))/50
0 = 6 -p/50
p = 300
From the initial condition, ...
A(0) = 300 +q = 40
q = -260
So, the complete solution is ...
A(t) = 300 -260e^(-t/50)
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The salt in the tank increases in exponentially decaying fashion from 40 grams to 300 grams with a time constant of 50 minutes.