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saw5 [17]
3 years ago
11

X : 14= 7: 8 can someone solve this for me and explain me

Mathematics
1 answer:
Vanyuwa [196]3 years ago
6 0

x:14 = 7:8

x:14 = x/14

7:8 = 7/8

x/14 = 7/8

Multiply the numerator of the 1st ratio with the denominator of the 2nd.

And multiply the numerator of the 2nd ratio with the denominator of the 1st.

Doing so, we get -

x * 8 = 7 * 14

So, 8x = 7 * 14

8x = 98

We divide 98 by 8 (transposition method)

x = 98/8

Therefore, x = 12.25

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The graph of f(x)=3×2 -3 is shown below. g(x) is a transformation of f(x). How would you write the equation for the function g(x
umka2103 [35]

A function assigns the values. The function of the graph g(x) is 3(2ˣ).

<h3>What is a Function?</h3>

A function assigns the value of each element of one set to the other specific element of another set.

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g(x) = f(x) + 3

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g(x) = 3(2ˣ)

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8 0
2 years ago
A crate has 272 red and green apples. How many green apples are there?
Rus_ich [418]

Answer:

149

Step-by-step explanation:

4 0
3 years ago
The area of the shaded segment is 100cm^2. Calculate the value of r.
Reil [10]
Hello, 

The formula for finding the area of a circular region is: A=  \frac{ \alpha *r^{2} }{2}

then:
A_{1} = \frac{80*r^{2} }{2}

With the two radius it is formed an isosceles triangle, so, we must obtain its area, but first we obtain the height and the base.

cos(40)= \frac{h}{r}  \\  \\ h= r*cos(40)\\ \\ \\ sen(40)= \frac{b}{r} \\ \\ b=r*sen(40)

Now we can find its area:
A_{2}=2* \frac{b*h}{2}  \\  \\ A_{2}= [r*sen(40)][r*cos(40)]\\  \\A_{2}= r^{2}*sen(40)*cos(40)

The subtraction of the two areas is 100cm^2, then:

A_{1}-A_{2}=100cm^{2} \\ (40*r^{2})-(r^{2}*sen(40)*cos(40) )=100cm^{2} \\ 39.51r^{2}=100cm^{2} \\ r^{2}=2.53cm^{2} \\ r=1.59cm

Answer: r= 1.59cm
7 0
3 years ago
Read 2 more answers
Find the solution(s) to the system of equations. Select all that apply.<br> y=x² - 4<br> y = -x-2
Andrej [43]

Answer:

x=1, y= -3

x= -2 y=0

Step-by-step explanation:

5 0
3 years ago
At 1 pm, there were 16 seagulls on the beach. At 3 pm, there were 40 seagulls. What is the constant rate of change?
beks73 [17]
<span>The answer is (change of amount) / (change of time). For the change of amount, the numerator is 40 seagulls - 16 seagulls, leaving a total of 24 seagulls. For the change of time, the denominator is 3 pm - 1 pm, leaving a total of a 2 hour difference. The answer becomes 24 seagulls / 2 hours, or 12 seagulls per hour when simplified.</span>
4 0
3 years ago
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