Which element is used as a rat poison and is found in the title of the murder mystery?

Chemistry

1 answer:

sergejj [24]3 years ago

6 0

The element that is used as a rat poison and found of the murder mystery is Arsenic.
Hope this helped you!

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What would happen to our solar system if the Sun had an even greater mass than it currently does?

motikmotik

Answer: If the Sun had an even greater mass then it currently does, it would have a larger gravitational pull and since it's heat would be closer to Earth, both by magnitude and gravity, life on Earth wouldn't be possible and life on Mars would be reality. Also, when the sun would explode, it would have a larger supernova and possibly create a white dwarf (something that only happens to red supergiant stars when they die), with a gravitational force so strong it wold have two beams of light coming out it's north and south poles (like a black hole).

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3 years ago

How many atoms are in 3.23 grams of copper

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2 years ago

If a reaction mixture initially contains 0.168 MSO2Cl2, what is the equilibrium concentration of Cl2 at 227 ∘C?

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Answer:

see explanation below

Explanation:

The question is incomplete. Here's the complete question:

Consider the following reaction: 

SO2Cl2 -----> SO2(g) + Cl2(g) 

Kc= 2.99 x 10^-7 at 227 degrees celcius 

If a reaction mixture initially contains 0.168 MSO2Cl2, what is the equilibrium concentration of Cl2 at 227 ∘C?

This is a problem of equilibrium, therefore, we need to solve this using the expression of equilibrium constant. To do that, we need to wirte an ICE chart and solve from there:

SOCl2 ---------> SO2 + Cl2 Kc = 2.99x10⁻⁷

i) 0.168 0 0

c) -x +x +x

e) 0.168-x x x

Writting the Kc expression:

Kc = [SO2] [Cl2] / [SOCl2]

Replacing the values from the chart:

2.99x10⁻⁷ = x² / 0.168 - x

However, Kc is a very very small value, therefore, we can assume that the value of "x" would be very small too, and we can neglect the 0.168-x and just round it to 0.168:

2.99x10⁻⁷ = x²/0.168

2.99x10⁻⁷ * 0.168 = x²

√5.02x10⁻⁸ = x

x = 2.24x10⁻⁴ M

This means then, that the concentration of Cl2 in equilibrium would be:

[Cl₂] = 2.24x10⁻⁴ M

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