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Doss [256]
3 years ago
7

3.25 x 10^24 molecules of dinitrogen pentoxide would be how many moles?

Chemistry
1 answer:
kow [346]3 years ago
6 0
<h3>Answer:</h3>

5.40 mol N₂O₅

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Using Dimensional Analysis
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
<h3>Explanation:</h3>

<u>Step 1: Define</u>

3.25 × 10²⁴ molecules N₂O₅

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

  1. Set up:                               \displaystyle 3.25 \cdot 10^{24} \ molecules \ N_2O_5(\frac{1 \ mol \ N_2O_5}{6.022 \cdot 10^{23} \ molecules \ N_2O_5})
  2. Multiply:                                                                                                           5.39688 \ mol \ N_2O_5

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

5.39688 mol N₂O₅ ≈ 5.40 mol N₂O₅

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The answer to your question is:  68.3%

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Limiting reactant = NH3

                   34kg of NH3 ------------------ 60 kg of Urea

                    145.1 kg       -------------------   x

                 x = (145.1 x 60) / 34

                x = 256 kg of Urea

Percent yield = 174.9 / 256 x 100

                     = 68.3%

 

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