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Doss [256]
3 years ago
7

3.25 x 10^24 molecules of dinitrogen pentoxide would be how many moles?

Chemistry
1 answer:
kow [346]3 years ago
6 0
<h3>Answer:</h3>

5.40 mol N₂O₅

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Using Dimensional Analysis
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
<h3>Explanation:</h3>

<u>Step 1: Define</u>

3.25 × 10²⁴ molecules N₂O₅

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

  1. Set up:                               \displaystyle 3.25 \cdot 10^{24} \ molecules \ N_2O_5(\frac{1 \ mol \ N_2O_5}{6.022 \cdot 10^{23} \ molecules \ N_2O_5})
  2. Multiply:                                                                                                           5.39688 \ mol \ N_2O_5

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

5.39688 mol N₂O₅ ≈ 5.40 mol N₂O₅

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What is the molar mass of 4.23 g of an elemental gas in a 2.5L container at 282K and 1.4 atm?
balu736 [363]

Answer:

27.98g/mol

Explanation:

Using ideal gas law equation;

PV = nRT

Where;

P = pressure (atm)

V = volume (L)

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A weather balloon is released in Houston when the pressure is 758.0 mmHg and 32.7°C. After the balloon reaches an altitude of 60
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Answer:

See explanation

Explanation:

From the information provided;

P1 = initial pressure = 758.0 mmHg

T1 = Initial temperature = 32.7°C + 273 = 305.7 K

V1 = Initial volume?

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V2 = Final volume =  425 L

T2= Final Temperature = 3.10°C + 273 = 276.1 K

P1V1/T1 = P2V2/T2

P1V1T2 =P2V2T1

V1 = P2V2T1/P1T2

V1 = 364.2 * 425 * 305.7/758.0 * 276.1

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B) Total pressure = 100.0 kPa

Pressure of Helium = 83.1 kPa

Pressure of carbon dioxide = 0.1000 kPa

Pressure of  oxygen ?

From Dalton's law of partial pressures;

PT = P1 + P2 +P3 +.........

Hence;

Poxygen = 100.0 kPa - (83.1 kPa + 0.1000 kPa)

Poxygen = 16.8 kPa

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