Answer:
The answer to your question is: 68.3%
Explanation:
Urea = ?
Theoretical yield
Ammonia 145.1 kg
Carbon dioxide = 211.4 kg
Urea = 174.9 kg
MW NH3 = 17kg
MW CO2 44 kg
MW Urea = 60 kg
2NH₃(aq) + CO₂(aq) → CH₄N₂O(aq) + H₂O(l)
34 44 kg 60kg
145.1 211.4 174.9
Limiting reactant = NH3
34kg of NH3 ------------------ 60 kg of Urea
145.1 kg ------------------- x
x = (145.1 x 60) / 34
x = 256 kg of Urea
Percent yield = 174.9 / 256 x 100
= 68.3%
The answer is D because Search Results
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