All categories

3 years ago

I need help fast thx

Mathematics

1 answer:

sammy [17]3 years ago

8 0

Vi = 56
Vf = 56 + 7(3) = 56 + 21 = 77

THe average is (Vf + Vi)/2

(77 + 56)/2 = 133/2 = 66.5 m/s

You might be interested in

Complementary and supplementary angles please answer please

kari74 [83]

Answer:

m<MON = 57

Hope this helps :)

3 0

3 years ago

Whats the error? I SOLVED AND CHECKED. Is it correct? Im confused… pls help il will give brainliest

Alchen [17]

Answer:

32 in represents perimeter u added length times width once which would only give half of the rectangle

Step-by-step explanation:

2(3w+8+w) =32

6w+16+2w =32

8w+16 = 32

8w=16

w=2

7 0

2 years ago

Find the least common denominator. (Enter the denominator only.)<br> 1/2, 5/6

Mama L [17]

Answer:

Step-by-step explanation:

2 goes into 6 evenly so two times three equals six so you multiply 1 by three and it gives you 3/6

8 0

4 years ago

Which of the following is a solution to 2cos2x − cos x − 1 = 0?

Pavel [41]

Answer:

Option A is correct.

Solution for the given equation is, $x = 0^{\circ}$

Step-by-step explanation:

Given that : $2\cos^2x -\cos x -1 =0$

Let $\cos x =y$

then our equation become;

$2y^2-y-1= 0$ .....[1]

A quadratic equation is of the form:

$ax^2+bx+c =0$ .....[2] where a, b and c are coefficient and the solution is given by;

$x = \frac{-b\pm \sqrt{b^2-4ac}}{2a}$

Comparing equation [1] and [2] we get;

a = 2 b = -1 and c =-1

then;

$y = \frac{-(-1)\pm \sqrt{(-1)^2-4(2)(-1)}}{2(2)}$

Simplify:

$y = \frac{ 1 \pm \sqrt{1+8}}{4}$

$y = \frac{ 1 \pm \sqrt{9}}{4}$

$y = \frac{ 1 \pm 3}{4}$

$y = \frac{1+3}{4}$ and $y = \frac{1 -3}{4}$

Simplify:

y = 1 and $y = -\frac{1}{2}$

Substitute y = cos x we have;

$\cos x = 1$

⇒ $x = 0^{\circ}$

and

$\cos x = -\frac{1}{2}$

⇒ $x = 120^{\circ} \text{and} x = 240^{\circ}$

The solution set: $\{0^{\circ}, 120^{\circ} , 240^{\circ}\}$

Therefore, the solution for the given equation $2\cos^2x -\cos x -1 =0$ is, $0^{\circ}$

8 0

4 years ago

Read 2 more answers

The second step in solving problems using order of operations is solving the

inna [77]

PEMDAS.....parenthesis, exponents, multiplication/division, addition/subtraction

so step 2 is solving the exponents <==

6 0

3 years ago

Read 2 more answers