The other endpoint would be (4,1)
Answer:
Nifal received $ 4 for washing the first car.
Nifal received $ 5 for washing the second car.
4 and 5 have a sum of 9.
Step-by-step explanation:
The problem can be rewritten as follows: Find the sum of two consecutive entire numbers equal to 9. That is:
Then, by eliminating y:
Now, let is clear 
:
Nifal received $ 4 for washing the first car.
The earning for the second car is: ()
Nifal received $ 5 for washing the second car.
4 and 5 have a sum of 9.
Answer:
1/4 > 1/5
Step-by-step explanation:
think of a candy bar. if you split it into 4 parts the prices would be bigger than if u had to break it into 5 parts. also remember that the smaller number eats the bigger number so the sign would be towards the 1/4
\left[x _{2}\right] = \left[ \frac{-1+i \,\sqrt{3}+2\,by+\left( -2\,i \right) \,\sqrt{3}\,by}{2^{\frac{2}{3}}\,\sqrt[3]{\left( 432\,by+\sqrt{\left( -6912+41472\,by+103680\,by^{2}+55296\,by^{3}\right) }\right) }}+\frac{\frac{ - \sqrt[3]{\left( 432\,by+\sqrt{\left( -6912+41472\,by+103680\,by^{2}+55296\,by^{3}\right) }\right) }}{24}+\left( \frac{-1}{24}\,i \right) \,\sqrt{3}\,\sqrt[3]{\left( 432\,by+\sqrt{\left( -6912+41472\,by+103680\,by^{2}+55296\,by^{3}\right) }\right) }}{\sqrt[3]{2}}\right][x2]=⎣⎢⎢⎢⎢⎡2323√(432by+√(−6912+41472by+103680by2+55296by3))−1+i√3+2by+(−2i)√3by+3√224−3√(432by+√(−6912+41472by+103680by2+55296by3))+(24−1i)√33√(432by+√(−6912+41472by+103680by2+55296by3))⎦⎥⎥⎥⎥⎤
totally answer.
Answer:
y=7.5x, y=9.25x, y=6x
Step-by-step explanation:
on the first table we have for 2 tikets $ 15 so the price for one ticket (also known as unit price) is 15/2= $ 7.5
the equation for the price of ticket must be
y= 7.5 x (where y is price you pay for x number of tikets)
on the second table you can pick that you have $37 for 4 tikets so unit price is 37/4= $9.25 per one ticket
y=9.25x
last table $12 for 2 tikets so for one ticket is 12/2=$6
y=6x
