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konstantin123 [22]
3 years ago
13

Why machines are never 100 percent efficient

Physics
2 answers:
dem82 [27]3 years ago
8 0
Machines are never 100% efficient because they are made by humans and we make errors and nothing we make is perfect, that's why the machines we build are not 100% accurate or efficient.
algol133 years ago
4 0
<span>The efficiency of an actual machine is never 100% because of the Second law of thermodynamics which states that the quality of energy will decay, eventually becoming heat. This means that some of the work put into the system is transformed (lost) into thermal energy(heat) therefore, causing the percent to reduce.</span>
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A 120-meter-long ski ift carries skiers from a station at the foot of a slope to a second station 40 m above. what is the IMA (i
Pepsi [2]
The ideal mechanical advantage (IMA) of an inclined plane is given by:
IMA =  \frac{L}{h}
where L is the length of the inclined plane while h is the height.
In our problem, L=120 m and h=40 m. Therefore, the IMA of the ski lift is
IMA= \frac{120 m}{40 m}=3
7 0
4 years ago
Mimas, a moon of Saturn, has an orbital radius of 1.62 × 108 m and an orbital period of about 23.21 h. Use Newton’s version of K
Drupady [299]

Answer:

3.60432\times 10^{26}\ kg

Explanation:

a = Orbital radius = 1.62\times 10^8\ m

T = Orbital period = 23.21 hours

G = Gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²

From Kepler's third law we get

M=\frac{4\pi^2a^3}{GT^2}\\\Rightarrow M=\frac{4\pi^2\times (1.62\times 10^8)^3}{6.67\times 10^{-11}\times (23.21\times 3600)^2}\\\Rightarrow M=3.60432\times 10^{26}\ kg

From the given data the mass of Saturn is 3.60432\times 10^{26}\ kg

8 0
3 years ago
30 points, brainiest, high school physics problem, please help with explanations.
Ymorist [56]

Answer:

I think the answer is C too

4 0
3 years ago
A balloon filled with helium gas has an average density of rhob = 0.22 kg/m3. The density of the air is about rhoa = 1.23 kg/m3.
MissTica

Answer:

a=g\left(\frac{\rho_a}{\rho_b}-1\right)

45.03681 m/s²

Explanation:

F_b = Buoyant force

W = Weight of the balloon

\rho_a = Density of air = 1.23 kg/m³

\rho_b = Density of balloon = 0.22 kg/m³

v_a = Volume of air

v_b = Volume of balloon

F_b=\rho_av_bg

W=\rho_bv_bg

g = Acceleration due to gravity = 9.81 m/s²

The net force acting on the balloon is

F=F_b-W\\\Rightarrow F=\rho_av_bg-\rho_bv_bg\\\Rightarrow \rho_bv_ba=\rho_av_bg-\rho_bv_bg\\\Rightarrow \rho_bv_ba=v_bg(\rho_a-\rho_b)\\\Rightarrow a=\frac{g}{\rho_b}(\rho_a-\rho_b)\\\Rightarrow a=g\left(\frac{\rho_a}{\rho_b}-1\right)

The equation is a=g\left(\frac{\rho_a}{\rho_b}-1\right)

a=g\left(\frac{\rho_a}{\rho_b}-1\right)\\\Rightarrow a=9.81\times \left(\frac{1.23}{0.22}-1\right)\\\Rightarrow a=45.03681\ m/s^2

The acceleration of the balloon is 45.03681 m/s²

8 0
3 years ago
An amusement park ride moves a rider at a constant speed of 14 meters per second in a horizontal circular path of radius 10. met
ASHA 777 [7]

Answer:

B) 2g

Explanation:

<u>Given the following data;</u>

Velocity, v = 14m/s

Radius, r = 10m

To find the centripetal acceleration;

Acceleration, a = \frac {v^{2}}{r}

Substituting into the equation, we have;

Acceleration, a = \frac {14^{2}}{10}

Acceleration, a = \frac {196}{10}

Acceleration, a = 19.6m/s²

In terms of acceleration due to gravity, g = 9.8m/s²

We would divide by g;

Acceleration, a = 19.6/9.8 = 2

Hence, centripetal acceleration = 2g

Therefore, the rider's centripetal acceleration in terms of g, the acceleration due to gravity is 2g.

4 0
3 years ago
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