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jonny [76]
3 years ago
12

How many electron flow through a light bulb each second if the current flow through the light bulb 0.75A.The electric charge of

one electron is 1.6 x 10-19C
Physics
1 answer:
castortr0y [4]3 years ago
4 0

Answer:

n=4.68\times 10^{18}

Explanation:

The current through the bulb, I = 0.75 A

We need to find the number of electrons flowing per second. We know that the electric current is given by :

I=\dfrac{ne}{t}\\\\n=\dfrac{It}{e}\\\\n=\dfrac{0.75\times 1}{1.6\times 10^{-19}}\\\\n=4.68\times 10^{18}

So, there are 4.68\times 10^{18} electrons flowing per second.

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What may thermal energy stores also be called?<br><br> PLEASE REALLY NEED THE HELP!
ollegr [7]

Answer:

The thermal energy is the sum of the potential energy and kinetic energy that is known to make all the particle in an object it is the energy that is responsible for its temperature heat is the flow of thermal energy thermal energy is the result of something that has some internal temperature which can be measured

3 0
2 years ago
A 5.0-kg box has an acceleration of 2.0 m/s2 when it is pulled by a horizontal force across a surface with μK = 0.50. Find the w
Maslowich

Answer:a) 34.5 N; b) 24.5 N; c) 10 N; d) 1J

Explanation: In order to solve this problem we have to used the second Newton law given by:

∑F= m*a

F-f=m*a where f is the friction force (uk*Normal), from this we have

F= m*a+f=5 Kg*2 m/s^2+0.5*5Kg*9.8 m/s^2= 34.5 N

then f=uk*N=0.5*5Kg*9.8 m/s^2= 24.5N

the net Force = (34.5-24.5)N= 10 N

Finally the work done by the net force is equal to kinetic energy change so

W=∫Force net*dr= 10 N* 0.1 m= 1J

7 0
3 years ago
Read 2 more answers
Please complete it if you know the answer. "The active region of a transistor is for.........
zubka84 [21]

Answer:

the active region is bound by cutoff region and saturation or power dissipation region.

Explanation:

5 0
3 years ago
A 200g block on a 50cm long string swings in a circle, it's frictionless and 75rpm. What is its speed and tension on string
krek1111 [17]
Angular velocity = (75x2pie)/60
                          =2.5pie ras^-1 
linear velocity(or speed) at end of string, v = radius x angular velocity
                                                           v= 0.5 x 2.5pie
                                                           v=3.93 ms^-1

tension of string (I beleve is centeral force aplied by string), F= (mv^2)/r
                                                                                      F= (0.2 x 3.93^2)/0.5
                                                                                      F=6.18 N
(sorry if wrong)
3 0
3 years ago
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How many elements are in the mixture pictured?<br> A. 7<br> B. 4<br> C. 3<br> D. 2
alex41 [277]

Answer:

C: 3

Explanation:

Cause of the colors

5 0
2 years ago
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