If the distance between two charges is halved, the electrical force between them increases by a factor 4.
In fact, the magnitude of the electric force between two charges is given by:

where
k is the Coulomb's constant
q1 and q2 are the two charges
r is the separation between the two charges
We see that the magnitude of the force F is inversely proportional to the square of the distance r. Therefore, if the radius is halved:

the magnitude of the force changes as follows:

so, the force increases by a factor 4.
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Answer:
In an inductive circuit, when frequency increases, the circuit current decreases and vice versa.
Explanation:
Answer:
The angle between the magnetic field and the wire’s velocity is 19.08 degrees.
Explanation:
Given that,
Potential difference, V = 53 mV
Length of the wire, l = 12 cm = 0.12 m
Magnetic field, B = 0.27 T
Speed of the wire, v = 5 m/s
Due to its motion, an emf is induced in the wire. It is given by :

Here,
is the angle between magnetic field and the wire’s velocity

So, the angle between the magnetic field and the wire’s velocity is 19.08 degrees.