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prisoha [69]
3 years ago
7

You are driving down the road at 30 mph (miles per hour) when you see the traffic light change to red. The red light is 300 feet

from you. How much time will it take you to stop? (please provide explanation)
Physics
1 answer:
RSB [31]3 years ago
8 0

Answer:

45 s

Explanation:

To find the time it takes to stop, we first find the deceleration, a of the car from

v² = u² + 2as and a = (v² - u²)/2s were v = final velocity of car = 0 mph = 0 m/s, u = initial velocity of car = 30 mph = 30 × 1609.34 ft ÷ 3600 s = 13.41 ft/s and s = distance = 300 ft. Substituting the values into a, we ave

a = (v² - u²)/2s = (0² - 13.41²)/2×300 = -0.3 ft/s²

We then find the time for this deceleration from v = u + at ⇒ t = (v - u)/a

t = (v - u)/a = (0 - 13.41 ft/s)/-0.3 ft/s² = - 13.41 ft/s/-0.3 ft/s² = 44.7 s ≅ 45 s

So it takes 45 seconds to stop.

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The coil of wire in the center of the screen encompasses an area through which magnetic field lines pass, so there is a magnetic
fredd [130]

Answer:

<em>No, the coil will produce no flow of current or potential difference.</em>

Explanation:

Magnetic field flux is the number of magnetic field line passing through a given area. It depends on the area and the magnetic field strength through this area. For electromagnetic induction to occur, there must be a constantly changing magnetic field. This is according to Faraday's law of electromagnetic induction that states that the induced EMF is directly proportional to the rate of change in flux ΔФ/Δt, and is also proportional to the number of turns on the coil. A changing magnetic field will lead to a break in the flux linkage, which induces current or potential difference on the coil. A stationary coil through a magnetic filed will therefore produce no electric flow of current or potential difference on the coil.

6 0
4 years ago
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5 0
3 years ago
A person walks in the following pattern: 3.1 km north, then 2.4 km west, and finally 5.2 km south. a) Sketch the vector diagram
zysi [14]

Answer:

d = 3.19 km

direction is given as

\theta = 41.2 degree South of West

Explanation:

Part b)

displacement is given as

d_1 = 3.1 \hat j

d_2 = 2.4 \hat i

d_3 = 5.2(-\hat j)

now we will have

d = d_1 + d_2 + d_3

d = 2.4 \hat i + (3.1 - 5.2)\hat j

d = 2.4 \hat i - 2.1 \hat j

total displacement is given as

d = \sqrt{2.4^2 + 2.1^2}

d = 3.19 km

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tan\theta = \frac{-2.1}{2.4}

\theta = 41.2 degree South of West

3 0
4 years ago
Electromagnetic radiation from a 8.25 mW laser is concentrated on a 1.23 mm2 area. Suppose a 1.12 nC static charge is in the bea
mylen [45]

Answer:

The maximum magnetic force is 2.637 x 10⁻¹² N

Explanation:

Given;

Power, P = 8.25 m W = 8.25 x 10⁻³ W

charge of the radiation, Q = 1.12 nC = 1.12 x 10⁻⁹ C

speed of the charge, v = 314 m/s

area of the conecntration, A = 1.23 mm² = 1.23 x 10⁻⁶ m²

The intensity of the radiation is calculated as;

I = \frac{P}{A} \\\\I = \frac{8.25 \times 10^{-3} \ W}{1.23 \ \times 10^{-6} \ m^2} \\\\I = 6,707.32 \ W/m^2

The maximum magnetic field is calculated using the following intensity formula;

I = \frac{cB_0^2}{2\mu_0} \\\\B_0 = \sqrt{\frac{2\mu_0 I}{c} } \\\\where;\\\\c \ is \ speed \ of \ light\\\\\mu_0 \ is \ permeability \ of \ free \ space\\\\B_0 \ is \ the \ maximum \ magnetic \ field\\\\B_0 = \sqrt{\frac{2 \times 4\pi \times 10^{-7} \times 6,707.32 }{3\times 10^8} } \\\\B_0 = 7.497 \times 10^{-6} \ T

The maximum magnetic force is calculated as;

F₀ = qvB₀

F₀ = (1.12 x 10⁻⁹) x (314) x (7.497 x 10⁻⁶)

F₀ = 2.637 x 10⁻¹² N

5 0
3 years ago
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