Can somebody help with this geometry question please

Mathematics

2 answers:

vova2212 [387]3 years ago

6 0

Answer:

X=25

3x-10=65

x+40=65

Step-by-step explanation:

klio [65]3 years ago

4 0

Answer:

25, 65, 65

Step-by-step explanation:

So first off, we should know that corresponding angles are congruent (equal). (3x-10) and (x+40) are corresponding angles.

So, because of this we set these two equal. 3x-10=x+40

Do the algebra. Subtract x on both sides and add 10 on both sides.

This gives you 2x = 50.

Divide by 2 on both sides.

This gives you x=25

Great. Now we know what x is, so x=25 Now we have to plug this in.

3(25) - 10 = 65

25+40 = 65

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ankoles [38]

Answer:

A. X(–2, 2), Y(–10, 2), Z(–6, 10)

Step-by-step explanation:

This looks a bit tough, but knowing that scale factors less than 1 are ½, ¼, etcetera, I come to this answer, also knowing that in the end, they must have an unproportional relationship.

I hope this is correct, and as always, I am joyous to assist anyone at anytime.

8 0

3 years ago

Please, I need help ASAP!

enot [183]

Answer:

Step-by-step explanation:

You can eliminate B and D because it’s using $\frac{g}{f}$ , but the question is asking $\frac{f}{g}$ . So it’s either A or C. They are both written correctly, but out of the two, A is correct because just that x ≠ $\sqrt{7}$ part of it is what makes it true.

The reason being is that the only thing that won’t make $\frac{2x+1}{x^{2}-7 }$ true is when the denominator equals 0, because anything divided by 0 is undefined. So, when you plug $\sqrt{7}$ for x in the denominator you get: $\sqrt{7^{2} } -7$ . The $\sqrt{7^{2} }$ part just turns into 7, and 7 - 7 is 0. So you don’t want x to equal $\sqrt{7}$ .