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3 years ago

9

Instructions: Find the missing length indicated.

1 answer:

TiliK225 [7]3 years ago

5 0

Answer:

? = 3

Step-by-step explanation:

The parallel segments shown divide the sides in the ratio

$\frac{6}{4}$ = $\frac{?}{2}$ ( cross- multiply )

4? = 12 ( divide both sides by 4 )

? = 3

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4 times a number is greater than -48.what are the possible values for the number ?

Keith_Richards [23]

The answer might be - 12

4 x -12 = 48

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4 years ago

Create a word problem using 30+2d as the answer

Tanzania [10]

Answer:

Sonya pays a flat fee of $30 for her phone bill and pays $2 per gigabyte she uses per month. Put Sonya's bill as an equation with <em>d</em> being how many gigabytes she uses per month.

Step-by-step explanation:

We get the flat fee of $30 from "30 + 2d" and the $2 per gigabyte from "30 + 2d" and since we want to find out Sonya's total bill, that's where the + in "30 + 2d" comes from. We want the variable to be <em>d</em> therefore <em>d</em> is how many gigabytes she uses per month.

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3 years ago

50 points! I understand A. and B. but I would really appreciate help with C.

FromTheMoon [43]

Answer:

$51.72\text{ cells per hour}$

Step-by-step explanation:

So, the function, P(t), represents the number of cells after t hours.

This means that the derivative, P'(t), represents the instantaneous rate of change (in cells per hour) at a certain point t.

C)

So, we are given that the quadratic curve of the trend is the function:

$P(t)=6.10t^2-9.28t+16.43$

To find the <em>instanteous</em> rate of growth at t=5 hours, we must first differentiate the function. So, differentiate with respect to t:

$\frac{d}{dt}[P(t)]=\frac{d}{dt}[6.10t^2-9.28t+16.43]$

Expand:

$P'(t)=\frac{d}{dt}[6.10t^2]+\frac{d}{dt}[-9.28t]+\frac{d}{dt}[16.43]$

Move the constant to the front using the constant multiple rule. The derivative of a constant is 0. So:

$P'(t)=6.10\frac{d}{dt}[t^2]-9.28\frac{d}{dt}[t]$

Differentiate. Use the power rule:

$P'(t)=6.10(2t)-9.28(1)$

Simplify:

$P'(t)=12.20t-9.28$

So, to find the instantaneous rate of growth at t=5, substitute 5 into our differentiated function:

$P'(5)=12.20(5)-9.28$

Multiply:

$P'(5)=61-9.28$

Subtract:

$P'(5)=51.72$

This tells us that at <em>exactly</em> t=5, the rate of growth is 51.72 cells per hour.

And we're done!

7 0

3 years ago

What is the answer to 8÷544

Stells [14]

8 ÷ 544 = 0.0147058824, 544 ÷ 8 = 68

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3 years ago

Ian and his brother are driving from city A to city B. The two cities are 282 miles apart. Ian drives at 47 miles per hour. How

leva [86]

I got 6 hours for this one.

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3 years ago