Answer:
Possibly the addition of oxygen from the atmosphere
Explanation:
Answer:
About 16.1 grams of oxygen gas.
Explanation:
The reaction between magnesium and oxygen can be described by the equation:
24.4 grams of Mg reacted with O₂ to produce 40.5 grams of MgO. We want to determine the mass of O₂ in the chemical change.
Compute using stoichiometry. From the equation, we know that two moles of MgO is produced from every one mole of O₂. Therefore, we can:
- Convert grams of MgO to moles of MgO.
- Moles of MgO to moles of O₂
- And moles of O₂ to grams of O₂.
The molecular weights of MgO and O₂ are 40.31 g/mol and 32.00 g/mol, respectively.
Dimensional analysis:
In conclusion, about 16.1 grams of oxygen gas was reacted.
You will obtain the same result if you compute with the 24.4 grams of Mg instead:
The correct response is A. The inner she'll contains 2 electrons and the outer shell contains 4 electrons.
Subatomic particles include electrons, the negatively charged, almost massless particles that nevertheless account for most of the size of the atom, and they include the heavier building blocks of the small but very dense nucleus of the atom, the positively charged protons and the electrically neutral neutrons.
And I don't see any of the particles. so I can only answer the first one.
The question is typed wrong. Assuming the correct question is
How many liters of 0.98 M H2SO4 solution would react completely with 3.5 moles Ca(OH)2 ?
Answer:-
3.571 litres
Explanation:-
The balanced chemical equation for this reaction is
H2SO4 + Ca(OH)2 = CaSO4 + 2 H2O
From the balanced chemical equation we see that
1 mole of Ca(OH)2 reacts with 1 mol of H2SO4.
∴3.5 moles of Ca(OH)2 reacts with 1 x 3.5 / 1 = 3.5 mol of H2SO4.
Strength of H2SO4 = 0.98 M
Volume of H2SO4 required = Number of moles of H2SO4 / Strength of H2SO4
= 3.5 moles / 0.98 M
= 3.571 litre
