From the stoichiometry of the balanced reaction equation, the correct statement are;
- For every 1 molecule of methane CH4 that reacts, 2 molecules of H2O are produced.
- For every 20 grams of methane (CH4) that reacts, 40 grams of H2O are produced.
- For every 200 moles of methane (CH4) that reacts, 400 moles of H2O are produced.
<h3>What is combustion?</h3>
The term combustion refers to the burning of fossil fuels for the purpose of energy production. The equation for reaction is CH4 + 2O2 ---> CO2 + 2H2O.
Using this equation as shown, the true statements are;
- For every 1 molecule of methane CH4 that reacts, 2 molecules of H2O are produced.
- For every 20 grams of methane (CH4) that reacts, 40 grams of H2O are produced.
- For every 200 moles of methane (CH4) that reacts, 400 moles of H2O are produced.
Learn more about combustion: brainly.com/question/15117038
Answer:
The correct answer is option A, that is, one valence electron in its third energy shell and option C, that is, 11 electrons and 11 protons.
Explanation:
The outermost electrons and the ones that take part in the process of bonding are termed as valence electrons. The atomic number of sodium is 11, thus, it possesses 11 protons and the atoms are neutral so it suggests that sodium has 11 electrons. By electronic configuration, it can be seen that in sodium, two electrons are present in the first shell, 8 in the second, and only one electron in the third shell, that is, 2.8.1. The electron present in the third shell is the valence electron.
Mass CoCl2 = 10.27 g
moles CoCl2 = 10.27 g/ 129.839 g/mol=0.07910
mass water = 17.40 - 10.27=7.13 g
moles water = 7.13 / 18.02 g/mol=0.396
0.396/ 0.07910=5
CoCl2 * 5 H2O
moles CaF2 = 85.8 g/ 78.0748 g/mol=1.10
moles Ca = 1.10
mass Ca = 1.10 x 40.078 g/mol=44.1 g
V = 44.1 / 1.55 =28.5 mL
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