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lapo4ka [179]
3 years ago
6

When the methyl ester of hexanoic acid is hydrolyzed in aqueous sodium hydroxide in the presence of heat, a homogeneous solution

results. When the hydrolysis solution is acidified with dilute aqueous hydrochloric acid, a new insoluble product forms. What is the structure of this insoluble product?

Chemistry
1 answer:
Dovator [93]3 years ago
4 0

Answer:

Hexanoic acid is formed as insoluble product

Explanation:

  • In aqueous sodium hydroxide, methyl ester of hexanoic acid hydrolyzes to produce soluble sodium hexanoate salt.
  • Upon addition of aqueous HCl, hexanoate ion is protonated to produce hexanoic acid which is insoluble in water.
  • Hence, upon acidification of hydrolysis solution, two separate layers (organic and aqueous) are formed.
  • Reaction are shown below.

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For the following reaction, 2.45 grams of methane (CH4) are allowed to react with 27.7 grams of carbon tetrachloride . methane (
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Answer:

The limiting reactant is CH₄

26.0g of CH₂Cl₂ is the maximum amount that can be formed

4.15g CCl₄ will remain

Explanation:

The reaction of methane, CH₄, with carbon tetrachloride, CCl₄ is:

CH₄ + CCl₄ → 2CH₂Cl₂

To find the maximum mass of dichloromethane that can be determined we need to find moles of methane and carbon tetrachloride:

<em>Moles CH₄:</em>

2.45g * (1mol / 16.04g) = 0.153 moles

<em>Moles CCl₄:</em>

27.7g * (1mol / 153.82g) = 0.180 moles

That means just 0.153 moles of CCl₄ will react until CH₄ is over.

<em>The limiting reactant is CH₄</em>

<em />

Assuming the whole 0.153 moles will react, the moles of CH₂Cl₂ will be:

0.153 moles CH₄ * (2 moles CH₂Cl₂ / 1 mole CH₄) = 0.306 moles of CH₂Cl₂

The mass is (Molar mass dichloromethane: 84.93g/mol):

0.306 moles of CH₂Cl₂  * (84.93g / mol) = 26.0g of CH₂Cl₂

The moles of CCl₄ that remain are:

0.180 moles - 0.153 moles = 0.027 moles

In grams:

0.027 moles * (153.82g / mol) = 4.15g CCl₄

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