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3 years ago

12

Sasha counted 24 feet in all of them in the barn how many dogs and birds and buyers do you think are in the barn today there are

four correct answers to this question

1 answer:

maw [93]3 years ago

3 0

(Assuming dogs have 4 feet, birds have 2 and buyers have 2)

One possibility is 4 dogs, 2 birds and 2 buyers [16 + 4 + 4]

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Find the surface area of a cube that is 5/8

vlabodo [156]

Answer:

A=6a2

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Can someone check my answer? i got 600.

lubasha [3.4K]

Answer:

Volume = 120 cubic cm

Step-by-step explanation:

We would apply the formula for determining the volume of a square bases pyramid which is expressed as

Volume = 1/3 x base area x height

From the diagram,

length of square base = 6 cm

The base area = 6^2 = 36

height = 10

Thus,

Volume = 1/3 x 3/6 x 10

Volume = 120 cubic cm

I hope this help you! :)

7 0

3 years ago

Kenny’s height is 1 meter 75 centimeters. How tall is Kenny in millimeters? REMEMBER: 1 meter = 100 centimeters : 1 centimeter =

Serga [27]

If I did the math right the answer should be 1,750

6 0

3 years ago

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Unit 8 right triangles and trigonometry homework 3 similar right triangles and geometric mean

Ugo [173]

The right triangles that have an altitude which forms two right triangles

are similar to the two right triangles formed.

Responses:

1. ΔLJK ~ ΔKJM

ΔLJK ~ ΔLKM

ΔKJM ~ ΔLKM

2. ΔYWZ ~ ΔZWX

ΔYWZ ~ ΔYZW

ΔZWX ~ ΔYZW

3. x = <u>4.8</u>

4. x ≈ <u>14.48</u>

5. x ≈ <u>11.37</u>

6. G.M. = <u>12·√3</u>

7. G.M. = <u>6·√5</u>

<u />

<h3>What condition guarantees the similarity of the right triangles?</h3>

1. ∠LMK = 90° given

∠JMK + ∠LMK = 180° linear pair angles

∠JMK = 180° - 90° = 90°

∠JKL ≅ ∠JMK All 90° angles are congruent

∠LJK ≅ ∠LJK reflexive property

<u>ΔLJK is similar to ΔKJM</u> by Angle–Angle, AA, similarity postulate

∠JLK ≅ ∠JLK by reflexive property

<u>ΔLJK is similar to ΔLKM</u> by AA similarity

By the property of equality for triangles that have equal interior angles, we have;

<u>ΔKJM ~ ΔLKM</u>

2. ∠YWZ ≅ ∠YWZ by reflexive property

∠WXZ ≅ ∠YZW all 90° angle are congruent

<u>ΔYWZ is similar to ΔZWX</u>, by AA similarity postulate

∠XYZ ≅ ∠WYZ by reflexive property

∠YXZ ≅ ∠YZW all 90° are congruent

<u>ΔYWZ is similar to ΔYZW</u> by AA similarity postulate

Therefore;

<u>ΔZWX ~ ΔYZW</u>

3. The ratio of corresponding sides in similar triangles are equal

From the similar triangles, we have;

$\dfrac{8}{10} = \mathbf{ \dfrac{x}{6}}$

8 × 6 = 10 × x

48 = 10·x

$x = \dfrac{48}{10} = \underline{4.8}$

3. From the similar triangles, we have;

$\mathbf{\dfrac{20}{29}} = \dfrac{x}{21}$

20 × 21 = x × 29

420 = 29·x

$x = \dfrac{420}{29 } \approx \underline{14.48}$

4. From the similar triangles, we have;

$\mathbf{\dfrac{20}{52}} = \dfrac{x}{48}$

20 × 48 = 52 × x

$x = \dfrac{20 \times 48}{52} = \dfrac{240}{13} \approx \underline{18.46}$

5. From the similar triangles, we have;

$\mathbf{\dfrac{13.2}{26}} = \dfrac{x}{22.4}$

13.2 × 22.4 = 26 × x

$x = \dfrac{13.2 \times 22.4}{26} \approx \underline{ 11.37}$

6. The geometric mean, G.M. is given by the formula;

$G.M. = \mathbf{\sqrt[n]{x_1 \times x_2 \times x_3 ... x_n}}$

The geometric mean of 16 and 27 is therefore;

$G.M. = \sqrt[2]{16 \times 27} = \sqrt[2]{432} = \sqrt[2]{144 \times 3} = \mathbf{12 \cdot \sqrt{3}}$

The geometric mean of 16 and 27 is <u>12·√3</u>

<u />

7. The geometric mean of 5 and 36 is found as follows;

$G.M. = \sqrt[2]{5 \times 36} = \sqrt[2]{180} = \sqrt[2]{36 \times 5} = \mathbf{ 6 \cdot \sqrt{5}}$

The geometric mean of 5 and 36 is <u>6·√5</u>

Learn more about the AA similarity postulate and geometric mean here:

brainly.com/question/12002948

brainly.com/question/12457640

7 0

2 years ago

The paint mixer wants to mix paint that is 30% gloss with paint that is 15% gloss to make 3.75 gallons of paint that is 20% glos

Kipish [7]

The paint mixer should mix 1.238 gallon paint that is 30 % gloss and 2.512 gallon paint that is 15 % gloss to get 3.75 gallon of paint that is 20 % gloss.

In this question we must determine the correct volumes of each paint to obtain a 20 % gloss with paint by means of weighted averages:

$c_{r} = x\cdot c_{a} +(1-x)\cdot c_{b}$ (1)

Where:

$x$ - Proportion of the paint that is 30 % gloss.
$c_{a}$ - Concentration ratio of the paint that is 30 % gloss.
$c_{b}$ - Concentration ratio of the paint that is 15 % gloss.
$c_{r}$ - Resulting concentration ratio

If we know that $c_{a} = 0.3$ , $c_{b} = 0.15$ and $c_{r} = 0.2$ , then the proportion of the paint that is 30 % gloss is:

$0.2 = 0.3\cdot x +(1-x)\cdot 0.15$

$0.2 = 0.15\cdot x+0.15$

$0.15\cdot x = 0.05$

$x = 0.33$

And the quantity of gallons needed of each paint are:

Paint (30 % gloss)

$V_{a} = 0.33\cdot (3.75\,gal)$

$V_{a} = 1.238\,gal$

Paint (15 % gloss)

$V_{b} = V-V_{a}$

$V_{b} = 3.75\,gal-1.238\,gal$

$V_{b} = 2..512\,gal$

The paint mixer should mix 1.238 gallon paint that is 30 % gloss and 2.512 gallon paint that is 15 % gloss to get 3.75 gallon of paint that is 20 % gloss.

To learn more on weighted averages, we kindly invite to check this question: brainly.com/question/18554478

8 0

2 years ago