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mina [271]
4 years ago
9

All sound is produced by: vibrations color a vacuum light

Chemistry
2 answers:
netineya [11]4 years ago
6 0

Answer:

vibrations

Explanation:

GalinKa [24]4 years ago
5 0
Vibrations of a medium
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29. Beetles undergo a complete change during their growth and development. This process
kifflom [539]

Answer:

ttfyggayxdy used to usual faith using

Explanation:

ttdrft

4 0
3 years ago
What might happen if earth did not rotate on its axis?
finlep [7]
It would be fatal for all.The ones on the side of sun would get everything but the ones farer than the sun wouldn't survive.There would be day forever on one side and night forever on other.
5 0
3 years ago
Fusion reactions are commercially viable because they require low energies to initiate and sustain a reaction.
guajiro [1.7K]

Answer:

False.

Explanation:

Fusion reactions are not yet commercially viable because they require extremely high energies to initiate and sustain a reaction.

3 0
4 years ago
Suppose of barium acetate is dissolved in of a aqueous solution of ammonium sulfate. Calculate the final molarity of barium cati
ollegr [7]

Explanation:

Let us assume that the given data is as follows.

   mass of barium acetate = 2.19 g

   volume = 150 ml = 0.150 L    (as 1 L = 1000 ml)

   concentration of the aqueous solution = 0.10 M

Therefore, the reaction equation will be as follows.

        Ba(C_{2}H_{3}O_{2})_{2} \rightarrow Ba^{2+} + 2C_{2}H_{3}O^{-}_{2}

Hence, moles of C_{2}H_{3}O^{-}_{2} = 2 \times Ba(C_{2}H_{3}O_{2})_{2}  .......... (1)

As,   No. of moles = \frac{mass}{\text{molar mass}}

Hence, moles of Ba(C_{2}H_{3}O_{2})_{2} will be calculated as follows.                          

     No. of moles = \frac{mass}{\text{molar mass}}  

                          =  \frac{2.19 g}{255.415 g/mol}   (molar mass of Ba(C_{2}H_{3}O_{2})_{2} is 255.415 g/mol)            

                       = 8.57 \times 10^{-3}

    Moles of C_{2}H_{3}O^{-}_{2} = 2 \times 8.57 \times 10^{-3}

                          = 0.01715 mol

Hence, final molarity will be as follows.

              Molarity = \frac{\text{no. of moles}}{volume}

                             = \frac{0.01715 mol}{0.150 L}

                             = 0.114 M

Thus, we can conclude that final molarity of barium cation in the solution is 0.114 M.

5 0
3 years ago
The reactant atoms are copper, hydrogen, nitrogen, and oxygen. Which reactant atom was oxidized in the reaction?
SCORPION-xisa [38]

Answer:

C. copper.

Explanation:

  • The atom which loses electrons (its oxidation sate be more positive) is the atom that is oxidized.
  • While, the atom which gains electrons (its oxidation sate be more negative) is the atom that is reduced.

  • Nitrogen:

It is oxidation sate is changed from (+5) in the reactants (NO₃⁻) to (+4) in the products (NO₂). N gains 1 electron

So, it is reduced.

  • Oxygen:

It is oxidation sate is the same (-2) in the reactants (NO₃⁻) and (-2) in the products (NO₂).

<em>So, it is neither be oxidized nor reduced.</em>

<em></em>

  • Copper:

It is oxidation sate is changed (0) in the reactants (Cu) to (+2) in the products (Cu²⁺). Cu loses 2 electrons.

<em>So, it is oxidized.</em>

<em></em>

  • Hydrogen:

It is oxidation sate is the same (+1) in the reactants (H⁺) and (+1) in the products (H₂O).

<em>So, it is neither be oxidized nor reduced.</em>

<em></em>

5 0
4 years ago
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