Explanation:
Immunoglobulin M is the first antibody produced on initial exposure to an antigen. It is also known as IgM.
It occurs as a primary response to the antigens against a particular baterium or virus. It is pentavalent in nature and has ten binding sites for antigens.
Therefore, it is concluded that when the body identifies a bacterium or a virus, it releases the antibody IgM.
Answer:
Mass = 255 g
Explanation:
Given data:
Number of moles of nitrogen = 7.5 mol
Mass of ammonia formed = ?
Solution:
Chemical equation:
3H₂ + N₂ → 2NH₃
Now we will compare the moles of nitrogen and ammonia.
N₂ : NH₃
1 : 2
7.5 : 2/1×7.5 = 15
Mass of ammonia:
Mass = number of moles × molar mass
Mass = 15 mol × 17 g/mol
Mass = 255 g
Answer:
The temperature change from the combustion of the glucose is 6.097°C.
Explanation:
Benzoic acid;
Enthaply of combustion of benzoic acid = 3,228 kJ/mol
Mass of benzoic acid = 0.570 g
Moles of benzoic acid = 
Energy released by 0.004667 moles of benzoic acid on combustion:

Heat capacity of the calorimeter = C
Change in temperature of the calorimeter = ΔT = 2.053°C



Glucose:
Enthaply of combustion of glucose= 2,780 kJ/mol.
Mass of glucose=2.900 g
Moles of glucose = 
Energy released by the 0.016097 moles of calorimeter combustion:

Heat capacity of the calorimeter = C (calculated above)
Change in temperature of the calorimeter on combustion of glucose = ΔT'



The temperature change from the combustion of the glucose is 6.097°C.
Answer:
B) 12
Explanation:
Given parameters:
Initial volume = 3L
Initial pressure = 4atm
Final pressure = 6atm
Unknown:
Final volume = ?
Solution:
To solve this problem, we apply Boyle's law which states that "the volume of a fixed mass of a gas varies inversely as the pressure changes if the temperature is constant".
P₁V₁ = P₂V₂
P and V are pressure and temperature values
1 and 2 are initial and final states.
PV product = 3 x 4 = 12