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kati45 [8]
3 years ago
5

Identify three nonmetal atoms that, when bonded covalently, have an argon electron configuration.

Chemistry
1 answer:
Advocard [28]3 years ago
8 0

Answer:

Phosphorus

Sulphur

And chlorine are non metals when bonded covalently gain electronic configuration of argon

Like PCl3

SO2 and HCl

Explanation:

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Which antibody does the body release when it identifies a bacterium or virus?
dlinn [17]

Explanation:

Immunoglobulin M is the first antibody produced on initial exposure to an antigen. It is also known as IgM.

It occurs as a primary response to the antigens against a particular baterium or virus. It is pentavalent in nature and has ten binding sites for antigens.

Therefore, it is concluded that when the body identifies a bacterium or a virus, it releases the antibody IgM.

6 0
3 years ago
Read 2 more answers
7.5 moles of nitrogen gas (N2) is formed in the following reaction. How many grams
AfilCa [17]

Answer:

Mass = 255 g

Explanation:

Given data:

Number of moles of nitrogen = 7.5 mol

Mass of ammonia formed = ?

Solution:

Chemical equation:

3H₂ + N₂      →    2NH₃

Now we will compare the moles of nitrogen and ammonia.

             N₂         :        NH₃

               1          :         2

              7.5       :       2/1×7.5 = 15

Mass of ammonia:

Mass = number of moles × molar mass

Mass = 15 mol × 17 g/mol

Mass = 255 g

6 0
3 years ago
The combustion of 0.570 g of benzoic acid (ΔHcomb = 3,228 kJ/mol; MW = 122.12 g/mol) in a bomb calorimeter increased the tempera
torisob [31]

Answer:

The temperature change from the combustion of the glucose is 6.097°C.

Explanation:

Benzoic acid;

Enthaply of combustion of benzoic acid = 3,228 kJ/mol

Mass of benzoic acid = 0.570 g

Moles of benzoic acid = \frac{0.570 g}{122.12 g/mol}=0.004667 mol

Energy released by 0.004667 moles of benzoic acid on combustion:

Q=3,228 kJ/mol \times 0.004667 mol=15.0668 kJ=15,066.8 J

Heat capacity of the calorimeter = C

Change in temperature of the calorimeter = ΔT = 2.053°C

Q=C\times \Delta T

15,066.8 J=C\times 2.053^oC

C=7,338.92 J/^oC

Glucose:

Enthaply of combustion of glucose= 2,780 kJ/mol.

Mass of glucose=2.900 g

Moles of glucose = \frac{2.900 g}{180.16 g/mol}=0.016097 mol

Energy released by the 0.016097 moles of calorimeter  combustion:

Q'=2,780 kJ/mol \times 0.016097 mol=44.7491 kJ=44,749.1 J

Heat capacity of the calorimeter = C (calculated above)

Change in temperature of the calorimeter on combustion of glucose = ΔT'

Q'=C\times \Delta T'

44,749.1 J=7,338.92 J/^oC\times \Delta T'

\Delta T'=6.097^oC

The temperature change from the combustion of the glucose is 6.097°C.

6 0
3 years ago
The following balanced equation shows the decomposition of water (H2O). According to the equation, how many oxygen atoms are in
EleoNora [17]
2 atoms of oxygen are reactants.
6 0
3 years ago
Read 2 more answers
A given sample of a gas has a volume of 3 liters at a
ycow [4]

Answer:

B) 12

Explanation:

Given parameters:

Initial volume  = 3L

Initial pressure  = 4atm

Final pressure  = 6atm

Unknown:

Final volume  = ?

Solution:

To solve this problem, we apply Boyle's law which states that "the volume of a fixed mass of a gas varies inversely as the pressure changes if the temperature is constant".

   P₁V₁  = P₂V₂

 P and V are pressure and temperature values

 1 and 2 are initial and final states.

    PV product  = 3 x 4 = 12

7 0
3 years ago
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